Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 7)
7.
A body is subjected to a tensile stress of 1200 MPa on one plane and another tensile stress of 600 MPa on a plane at right angles to the former. It is also subjected to a shear stress of 400 MPa on the same planes. The maximum normal stress will be
Discussion:
57 comments Page 4 of 6.
ABHI BANSAL said:
1 decade ago
By using mohr's circle we can easily find out the maximum principle stress.
Rashid Khan Kakar said:
4 years ago
It's subject to tow perpendicular normal stresses on oblique section.
(1)
Pradeep yadav said:
10 years ago
@Suresh you have any formula for normal stress in this manner.
Mona said:
1 decade ago
I need the solution urgently need. Can you please solve again?
Zaid said:
1 decade ago
Normal stress = (Fx+Fy)/2 + 1/2* ((Fx-Fy)^2 +4(txy)^2)).
Shahrukh ansari said:
1 decade ago
Max. normal stress is equal to max. principal stress.
Rahul prajapati said:
1 decade ago
Normal stress and maximum stress difference tell me.
Dadi Lavanya lahari said:
12 months ago
Thank you for explaining the answer @Sagarbankar.
Rahul said:
9 years ago
Normal stress = (sum of stress/2) = 900 answer.
Suresh said:
1 decade ago
The maximum stress = x+y-z.
= 1400+600-200.
= 1400+600-200.
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