Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 7)
7.
A body is subjected to a tensile stress of 1200 MPa on one plane and another tensile stress of 600 MPa on a plane at right angles to the former. It is also subjected to a shear stress of 400 MPa on the same planes. The maximum normal stress will be
Discussion:
57 comments Page 1 of 6.
Umesh said:
1 decade ago
Use max. Principal stress formula.
ABHI BANSAL said:
1 decade ago
By using mohr's circle we can easily find out the maximum principle stress.
Amol Kamale said:
1 decade ago
Assume stress in X direction(X) = 1200.
Stress in Y direction(Y) = 600.
Shear stress(S) = 400.
Max. Normal stress=(X+Y)/2+Sqrt(((X-Y)/2)square+S square).
=(1200+600)/2 + sqrt(300 square + 400 square).
=1400 mpa.
Stress in Y direction(Y) = 600.
Shear stress(S) = 400.
Max. Normal stress=(X+Y)/2+Sqrt(((X-Y)/2)square+S square).
=(1200+600)/2 + sqrt(300 square + 400 square).
=1400 mpa.
Rohit said:
1 decade ago
@Amol is this formula applicable for finding Max. Normal stress in all types of questions?
Amol Kamale said:
1 decade ago
Yes, this formula applicable for finding Max. Normal stress in all types of questions.
Kaushl said:
1 decade ago
Normal stress & principal stress are not same, then how we can use the formula of max principal stress for finding normal stress.
Nepolepn pradhan said:
1 decade ago
Let,tensile stress on one plane(t.s1) = 1200mpa.
Tensile stress on another plane(t.s2) = 600mpa.
Shear stress (s.s) = 400mpa.
Now using major principal stress formula = [(t.s1+t.s2)/2]+sqrt[{(t.s1-t.s2)*(t.s1-t.s2)}/2 +(s.s*s.s)].
Tensile stress on another plane(t.s2) = 600mpa.
Shear stress (s.s) = 400mpa.
Now using major principal stress formula = [(t.s1+t.s2)/2]+sqrt[{(t.s1-t.s2)*(t.s1-t.s2)}/2 +(s.s*s.s)].
Mahender Rana said:
1 decade ago
Yes I am agree with @Kaushal that normal and principal stresses are not same, then how it is possible to use same formula.
Khagesh said:
1 decade ago
We can get max normal stress from: x+y=n1+n2.
The formula given above is wrong for max normal stress if you don't believe it solve it.
The formula given above is wrong for max normal stress if you don't believe it solve it.
Khagesh said:
1 decade ago
Principal stress are maximum and minimum normal stress which may be developed on a loaded body.
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