Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 7)
7.
A body is subjected to a tensile stress of 1200 MPa on one plane and another tensile stress of 600 MPa on a plane at right angles to the former. It is also subjected to a shear stress of 400 MPa on the same planes. The maximum normal stress will be
Discussion:
57 comments Page 2 of 6.
Manoj Nayak said:
9 years ago
Solution is very simple. Ans is 1400.
Explanation:
Normal stress =((x+y)÷2) + √ ((x - y)÷2) + (shear stress)^2 where x = 1200 & y= 600.
Explanation:
Normal stress =((x+y)÷2) + √ ((x - y)÷2) + (shear stress)^2 where x = 1200 & y= 600.
Mustaf HD said:
7 years ago
Normal stress= (x+y)/2-[{(x-y)/2}cos2@]-(z*sin2θ).
Z-shear stress.
θ perpendicular means 90.
900-(-300)-0=1200.
The answer should be 1200.
Z-shear stress.
θ perpendicular means 90.
900-(-300)-0=1200.
The answer should be 1200.
(5)
Sachin pravin patil said:
9 years ago
The resultant tensile stress is (1200+600)/2 =900 MPA shear stress =400 Mpa using maximum normal stress theory 1/2(900+ 900^2+4 * 400^2)= 1400Mpa.
Hareshkumar said:
8 years ago
The resultant tensile stress is (1200+600)/2 =900 MPA shear stress =400 Mpa using maximum normal stress theory 1/2(900+ 900^2+4 * 400^2) = 1400Mpa.
Kamal Talukdar. said:
7 years ago
1200+600/2+1/2 * (1200-600)^2+4 * (400)^2.
= 1800/2+1/2 * (600)^2+4 * (400)^2,
= 900+1/2 * 360000+640000,
= 900+1/2*1000,
= 900+500.
= 1400MPa.
= 1800/2+1/2 * (600)^2+4 * (400)^2,
= 900+1/2 * 360000+640000,
= 900+1/2*1000,
= 900+500.
= 1400MPa.
(25)
Nabin said:
1 decade ago
LET
T.S1=1200 and T. S2=600 and S.S=400 normal stress = T.S1+T.S2-S.S.
Then 1200+600-400 = 1400. So maximum normal stress = 1400 Mpa.
T.S1=1200 and T. S2=600 and S.S=400 normal stress = T.S1+T.S2-S.S.
Then 1200+600-400 = 1400. So maximum normal stress = 1400 Mpa.
Khagesh said:
1 decade ago
We can get max normal stress from: x+y=n1+n2.
The formula given above is wrong for max normal stress if you don't believe it solve it.
The formula given above is wrong for max normal stress if you don't believe it solve it.
Kaushl said:
1 decade ago
Normal stress & principal stress are not same, then how we can use the formula of max principal stress for finding normal stress.
Mahender Rana said:
1 decade ago
Yes I am agree with @Kaushal that normal and principal stresses are not same, then how it is possible to use same formula.
Kaushal roy said:
7 years ago
Two different stress act on a member design should be based on max principal stress so here we find max principal stress.
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