Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 34)
34.
When a bar is cooled to - 5°C, it will develop
Discussion:
105 comments Page 1 of 11.
Phaneendra said:
3 years ago
If the bar is cooled, it will shrink. But the internal forces will resist that by producing force in opposite direction to shrinkage which means the internal forces produce tension. So the answer is tensile stress if the bar is fixed.
But here the bar is not under any restraints. So there will be no stress.
But here the bar is not under any restraints. So there will be no stress.
(11)
Sujit Mundhe said:
5 years ago
We know that Stress means Internal Stress/Area
If bar at -5' obviously it goes to compression & hence to resist this compression tensile stress is develop in rod to get its actual length.
If bar at -5' obviously it goes to compression & hence to resist this compression tensile stress is develop in rod to get its actual length.
(2)
Atanu said:
5 years ago
When a bar is cooled to - 5° C, it will develop.
Actually, this question denoted 'a bar '.
It is not Mentioned as the bar is fixed, hinged, both sides fixed it. So the bar is free, not fixed and hinged.
That's why the answer is ' no stress '.
(If it is mentioned as "one side is fixed" then the answer is compressive stress generate).
Thank you.
Actually, this question denoted 'a bar '.
It is not Mentioned as the bar is fixed, hinged, both sides fixed it. So the bar is free, not fixed and hinged.
That's why the answer is ' no stress '.
(If it is mentioned as "one side is fixed" then the answer is compressive stress generate).
Thank you.
(2)
Ishfaq paray said:
4 years ago
Correct answer is tensile stress.
Here -5 degrees denotes that there will be an initial temperature
Thermal stress= E alpha ΔT,
ΔT= T2-T1.
If T2 is -10 degrees that means ΔT =-10-(-5)=-5 degree which means compressive,
If T2 =10 degree.
ΔT= 10-(-5)=15 which means tensile stress . So the answer will be tensile.
Here -5 degrees denotes that there will be an initial temperature
Thermal stress= E alpha ΔT,
ΔT= T2-T1.
If T2 is -10 degrees that means ΔT =-10-(-5)=-5 degree which means compressive,
If T2 =10 degree.
ΔT= 10-(-5)=15 which means tensile stress . So the answer will be tensile.
(2)
Rajesh kumar patel said:
5 years ago
The right answer is compressive stress.
And when free bar then hired then no thermal stress dovlepod.
And when free bar then hired then no thermal stress dovlepod.
(1)
Ajant pandey said:
4 years ago
If the temperature of the bar is lowered, then the nature of stress & strain will be?
(1)
Akki said:
1 decade ago
Why if bar is cooled then bar in compressive stress? Please explain me.
Mahendra said:
1 decade ago
The tensile stress answer may be correct when bar is fixed at both end otherwise no stress will developed in bar.
Rushi said:
1 decade ago
It's not sufficient ans-please, formulation description required.
Arun said:
1 decade ago
When a bar is cooled to -5 temp it must goes to compressive stress. Whenever a body is cooled its undergoes shrinkage. So compressive stresses are developed.
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