Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 28)
28.
The maximum stress produced in a bar of tapering section is at
Discussion:
13 comments Page 1 of 2.
Ashish said:
1 decade ago
Since stress= (force/area).
So if area decreases stress increases so at smaller end area is small so high stress over there.
So if area decreases stress increases so at smaller end area is small so high stress over there.
KODURI.SANKARACHARYULU said:
1 decade ago
Obviously, Stress is inversely proportional to the area. So in small end area of section is very small when compared to large side so. Ultimately stress should be more at small end.
Varma said:
1 decade ago
Stress is inversely proportional to the cross-sectional area of specimen taken under consideration.
Sahib said:
1 decade ago
Stress inversely in relation to the area under consideration.
G Sunil Reddy said:
1 decade ago
Stress is inversely proportional to area so smaller end take more stress.
Chandra prakash said:
9 years ago
We know that,
Stress = load/area.
I.e. Stress is inversely proportional to the area.
So, the max. Stress is produced in at the smaller end of the bar because their area is less.
Stress = load/area.
I.e. Stress is inversely proportional to the area.
So, the max. Stress is produced in at the smaller end of the bar because their area is less.
Sathish said:
8 years ago
It is Based on force acting.
(1)
Anomies said:
7 years ago
The bar must be hanging vertically downward.
Hence max stress should act on larger area.
Hence max stress should act on larger area.
Basar sk said:
6 years ago
As we know, stress inversely proportional to the area. So where the area is minimum stress is maximum. So the answer is a smaller end.
ANUTOSH DAS said:
6 years ago
STRESS = FORCE/AREA.
(1)
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