Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 28)
28.
The maximum stress produced in a bar of tapering section is at
Discussion:
13 comments Page 1 of 2.
Shubham Bhuva said:
4 years ago
Absolutely stress is inversely proportional to area.
So, smaller end area is becoming minimum so answer is smaller end.
So, smaller end area is becoming minimum so answer is smaller end.
(4)
Sathish said:
8 years ago
It is Based on force acting.
(1)
ANUTOSH DAS said:
6 years ago
STRESS = FORCE/AREA.
(1)
RAHUL KUMAR GUPTA said:
5 years ago
As we know that stress is inversely proportional to area. It means area increase then obviously stress decreased. Area of small end is less than larger end. So maximum stress produced at small end.
(1)
Ashish said:
1 decade ago
Since stress= (force/area).
So if area decreases stress increases so at smaller end area is small so high stress over there.
So if area decreases stress increases so at smaller end area is small so high stress over there.
KODURI.SANKARACHARYULU said:
1 decade ago
Obviously, Stress is inversely proportional to the area. So in small end area of section is very small when compared to large side so. Ultimately stress should be more at small end.
Varma said:
1 decade ago
Stress is inversely proportional to the cross-sectional area of specimen taken under consideration.
Sahib said:
1 decade ago
Stress inversely in relation to the area under consideration.
G Sunil Reddy said:
1 decade ago
Stress is inversely proportional to area so smaller end take more stress.
Chandra prakash said:
9 years ago
We know that,
Stress = load/area.
I.e. Stress is inversely proportional to the area.
So, the max. Stress is produced in at the smaller end of the bar because their area is less.
Stress = load/area.
I.e. Stress is inversely proportional to the area.
So, the max. Stress is produced in at the smaller end of the bar because their area is less.
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