Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion
Discussion Forum : Hydraulics and Fluid Mechanics - Section 1 (Q.No. 11)
11.
The length AB of a pipe ABC in which the liquid is flowing has diameter (d1) and is suddenly enlarged to diameter (d2) at B which is constant for the length BC. The loss of head due to sudden enlargement is
Discussion:
32 comments Page 1 of 4.
Amresh kumar sinha said:
1 decade ago
Bernaullie's principle: As with having different areas of flow of a fluid through a convergent pipe,give us a reason to apply conservation of energy equation having relation with pressure,velocity and density of the respective fluid.
As for a pipe having two ends with different dimensions of respectively pressure,velocity and densities then we have the equation as-{(p1/wg+v1square/2g+z1)-(p2/wg+v2square/2g+z2)}=constant.
As for a pipe having two ends with different dimensions of respectively pressure,velocity and densities then we have the equation as-{(p1/wg+v1square/2g+z1)-(p2/wg+v2square/2g+z2)}=constant.
Ballamudi mounica said:
1 decade ago
We know the Bernoulli's equation.
From that we obtain,
p1/wg+v1^2/2g+z1 = p2/wg+v2^2/2g+z2.
z1=z2 from this we get,
p1/wg-p2/wg = v1^2/2g-v2^2/2g.
= (v1-v2)^2/2g.
Which is loss of head bcoz p1-p2/wg=H where h=head loss
and wg=row.
From that we obtain,
p1/wg+v1^2/2g+z1 = p2/wg+v2^2/2g+z2.
z1=z2 from this we get,
p1/wg-p2/wg = v1^2/2g-v2^2/2g.
= (v1-v2)^2/2g.
Which is loss of head bcoz p1-p2/wg=H where h=head loss
and wg=row.
MD MOBIN ALAM said:
1 decade ago
Minor losses due to sudden expansion By bernoulli's eq.
h=(v1^ 2-v2^2/2g)-(p1-p2/$g).
And by momentum eq,
(p1-p2/$g)=v2(v2-v1)/g and put the value in above eq,
Then,
h=(v1-v2)^2/2g.
h=(v1^ 2-v2^2/2g)-(p1-p2/$g).
And by momentum eq,
(p1-p2/$g)=v2(v2-v1)/g and put the value in above eq,
Then,
h=(v1-v2)^2/2g.
Vishnu said:
6 years ago
Option C is correct.
Head loss due to sudden enlargement,
h = V1^2(1-A1/A2)^2 /2g.
And we know A1V1=A2V2,
Applying this on the first equation will give the correct answer (i.e. C).
Head loss due to sudden enlargement,
h = V1^2(1-A1/A2)^2 /2g.
And we know A1V1=A2V2,
Applying this on the first equation will give the correct answer (i.e. C).
Mahur said:
8 years ago
We know Bernoulli equation.
p1/w + v1^2/2g + Z1 = p2/w + v2^2/2g + Z2.
if p1 = p2.
Head loss Z2 - Z1 = (V1^2 - V2^2)/2g. So, OPTION D CORRECT.
p1/w + v1^2/2g + Z1 = p2/w + v2^2/2g + Z2.
if p1 = p2.
Head loss Z2 - Z1 = (V1^2 - V2^2)/2g. So, OPTION D CORRECT.
(1)
Anup Kumar said:
1 decade ago
I Think that Answer is D.
Becoz according to Bernoulli's Equation.
H = P1/wg-p2/wg = (v1^2-v2^2)/2g.
Becoz according to Bernoulli's Equation.
H = P1/wg-p2/wg = (v1^2-v2^2)/2g.
Niranjan Bisht said:
8 years ago
Opt-c is correct as sudden enlargement of pipe, so change in momentum is also taken into acc.
Jasim said:
6 years ago
Option C is correct.
REF:: Flow through pipe(chapter 11).
Dr.R.K. Bansal
Topics 11.4.1
REF:: Flow through pipe(chapter 11).
Dr.R.K. Bansal
Topics 11.4.1
(2)
Varun said:
7 years ago
@Niranjan.
Fine momentum is taken into account but please explain it in brief.
Fine momentum is taken into account but please explain it in brief.
Rajkotha said:
4 years ago
Sudden enlargement = (v1-v2)^2/2g.
Sudden contarction = 0.5v^2/2g.
Sudden contarction = 0.5v^2/2g.
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