Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion

Discussion Forum : Hydraulics and Fluid Mechanics - Section 5 (Q.No. 7)
7.
A jet of water discharging from a 40 mm diameter orifice has a diameter of 32 mm at its vena contracta. The coefficient of contraction is
0.46
0.64
0.78
0.87
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
11 comments Page 1 of 2.

Malik said:   1 decade ago
Coefficient of contraction = Diameter of orifice/Diameter of Jet = 32/40 = 0.8.

Bharat said:   1 decade ago
Coefficient of contraction = Area of vena contracta/Area of orifice.

Fakhre Alam said:   1 decade ago
Cc = D^2 of vena contracta/D^2 of orifice.

Gopala krishnan said:   1 decade ago
Coefficient of contraction=area of jet/area of orifice.

= ((3.14*32*32)/4)/((3.14*40*40)/4).

= 803.84/1256 = 0.64.

Expert's Advice said:   1 decade ago
Coefficient of contraction = Diameter of vena contracta square/Diameter of orifice square.

Prvaeen kumar said:   9 years ago
CC = Area at vena contracta/ Area of orifice.

The typical value may be taken as 0.64 for a sharp orifice (concentric with the flow channel).

Vishal said:   8 years ago
COC= Area of a jet at vena contracta/Area of orifice.

So, (Dv)2/(Do)2.

32*32/40*40.
= 0.64.

Golla lakshmanna said:   7 years ago
Cc = Ac/A .
Ac = (π/4)d*2 = (3.14/4)*(32*32),
A = (π/4)d*2=(3.14/4)*(40*40),
Cc = 0.64.

Golla lakshmanna said:   7 years ago
Cc=Ac/A.
Ac=(π/4)d*2 = (3.14/4)*(32*32),
A=(π/4)d*2=(3.14/4)*(40*40),
Cc=0.64.

Golla lakshmanna said:   7 years ago
Cc=Ac/A.
Ac=(π/4)d*2 = (3.14/4)*(32*32),
A=(π/4)d*2=(3.14/4)*(40*40),
Cc=0.64.


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