Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion
Discussion Forum : Hydraulics and Fluid Mechanics - Section 5 (Q.No. 7)
7.
A jet of water discharging from a 40 mm diameter orifice has a diameter of 32 mm at its vena contracta. The coefficient of contraction is
Discussion:
11 comments Page 1 of 2.
MUHAMMAD NABI said:
4 years ago
Cc = area of jet/area of orifice
Cc = π r ^2/&pi r^2
Cc = r^2/r^2
As r = D/2.
32/2 = 16,
40/2 = 20,
Cc = 16^2/20^2.
Cc = 0.64.
Cc = π r ^2/&pi r^2
Cc = r^2/r^2
As r = D/2.
32/2 = 16,
40/2 = 20,
Cc = 16^2/20^2.
Cc = 0.64.
(1)
Malik said:
1 decade ago
Coefficient of contraction = Diameter of orifice/Diameter of Jet = 32/40 = 0.8.
Bharat said:
1 decade ago
Coefficient of contraction = Area of vena contracta/Area of orifice.
Fakhre Alam said:
1 decade ago
Cc = D^2 of vena contracta/D^2 of orifice.
Gopala krishnan said:
1 decade ago
Coefficient of contraction=area of jet/area of orifice.
= ((3.14*32*32)/4)/((3.14*40*40)/4).
= 803.84/1256 = 0.64.
= ((3.14*32*32)/4)/((3.14*40*40)/4).
= 803.84/1256 = 0.64.
Expert's Advice said:
1 decade ago
Coefficient of contraction = Diameter of vena contracta square/Diameter of orifice square.
Prvaeen kumar said:
9 years ago
CC = Area at vena contracta/ Area of orifice.
The typical value may be taken as 0.64 for a sharp orifice (concentric with the flow channel).
The typical value may be taken as 0.64 for a sharp orifice (concentric with the flow channel).
Vishal said:
8 years ago
COC= Area of a jet at vena contracta/Area of orifice.
So, (Dv)2/(Do)2.
32*32/40*40.
= 0.64.
So, (Dv)2/(Do)2.
32*32/40*40.
= 0.64.
Golla lakshmanna said:
7 years ago
Cc=Ac/A.
Ac=(π/4)d*2 = (3.14/4)*(32*32),
A=(π/4)d*2=(3.14/4)*(40*40),
Cc=0.64.
Ac=(π/4)d*2 = (3.14/4)*(32*32),
A=(π/4)d*2=(3.14/4)*(40*40),
Cc=0.64.
Golla lakshmanna said:
7 years ago
Cc=Ac/A.
Ac=(π/4)d*2 = (3.14/4)*(32*32),
A=(π/4)d*2=(3.14/4)*(40*40),
Cc=0.64.
Ac=(π/4)d*2 = (3.14/4)*(32*32),
A=(π/4)d*2=(3.14/4)*(40*40),
Cc=0.64.
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