Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion
Discussion Forum : Hydraulics and Fluid Mechanics - Section 2 (Q.No. 15)
15.
A water tank contains 1.3 m deep water. The pressure exerted by the water per metre length of the tank is
Discussion:
25 comments Page 2 of 3.
Arun kumar said:
8 years ago
P=ρgh^2/2
ρ=1000
g=9.81
h=1.3
Than put,
P=1000*9.81*1.3*1.3/2=8289.45N=8.289KN.
ρ=1000
g=9.81
h=1.3
Than put,
P=1000*9.81*1.3*1.3/2=8289.45N=8.289KN.
(1)
Mohammad Zubair Khan said:
5 years ago
10^3 or 1000 being multiplied to convert the unit from N (Newton) to KN (Kilo Newton).
Rakshit Khatri said:
7 years ago
@Aman Kumar.
The pressure exerted by the water per metre length of the tank.
The pressure exerted by the water per metre length of the tank.
Abhishek said:
4 years ago
pressure exerted per unit length = ωH2/2.
= (9. 81x103x1.32)/2.
= 8.29 KN.
= (9. 81x103x1.32)/2.
= 8.29 KN.
(1)
NILADRI NAG said:
5 years ago
Why 1000 is being multiplied with the equation? Anyone explain.
Hema said:
9 years ago
Can anyone explain how that equation comes?
Amit said:
9 years ago
Thanks for giving the correct explanation.
Vaibhav said:
8 years ago
Can anyone explain me how that area came?
Ram said:
8 years ago
Thank you all for the explanation.
Vinayak said:
9 years ago
Thank you for giving the solution.
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