Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 50)
50.
If two bodies having masses m1 and m2 (m1>m2) have equal kinetic energies, the momentum of body having mass m1 is __________ the momentum of body having mass m2.
Discussion:
32 comments Page 3 of 4.
Kingshuk said:
1 decade ago
@Harish.
You are wrong. Velocities can not be equal in order to attain equal K. E where m1>m2.
You are wrong. Velocities can not be equal in order to attain equal K. E where m1>m2.
Nitin said:
10 years ago
@Sashi.
But don't forget momentum also depends upon velocity and you missed that.
But don't forget momentum also depends upon velocity and you missed that.
Satya Jeet Verma said:
6 years ago
K.E= p^2/2*m.
KE1=KE2.
P1^2/2*m1=P2^/2*m2.
since m1>m2.
So P1>P2.
KE1=KE2.
P1^2/2*m1=P2^/2*m2.
since m1>m2.
So P1>P2.
Lokesh said:
1 decade ago
K.E. = 1/2mv^2.
.
. . v1 = v2.
Momentum = mv.
So, m1v1 > m2v2.
.
. . v1 = v2.
Momentum = mv.
So, m1v1 > m2v2.
Gaurav said:
1 decade ago
Consider m1 = 4, v1 = 2, m2 = 1, v2 = 4.
Here m1v1>m2v2 :).
Here m1v1>m2v2 :).
Hassan rizwi said:
7 years ago
Simple greater the mass greater the momentum.
(1)
Mohsin Ali said:
3 years ago
You are absolutely right @Johny.
Suresh kumawat said:
1 decade ago
How can you say that v1 = v2.
(1)
Dhiru said:
10 years ago
K.E-p^2/2m.
p - Momentum.
p - Momentum.
Melkamu said:
6 years ago
Thanks all for explaining.
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