Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 50)
50.
If two bodies having masses m1 and m2 (m1>m2) have equal kinetic energies, the momentum of body having mass m1 is __________ the momentum of body having mass m2.
Discussion:
32 comments Page 3 of 4.
Nitin said:
10 years ago
@Sashi.
But don't forget momentum also depends upon velocity and you missed that.
But don't forget momentum also depends upon velocity and you missed that.
Sandy said:
10 years ago
Since Momentum = Mass Acceleration.
That means Momentum is directly proportional to the mass.
So, if mass is more the momentum will also be more.
That means Momentum is directly proportional to the mass.
So, if mass is more the momentum will also be more.
Sasi said:
1 decade ago
Momentum = Mass*Velocity.
Here (mass) m1>m2.
Hence momentum of body 1 is greater than the body 2.
Here (mass) m1>m2.
Hence momentum of body 1 is greater than the body 2.
Sasi said:
1 decade ago
Momentum = Mass*Velocity.
Here (mass) m1>m2.
Hence momentum of body 1 is greater than the body 2.
Here (mass) m1>m2.
Hence momentum of body 1 is greater than the body 2.
Kingshuk said:
1 decade ago
@Harish.
You are wrong. Velocities can not be equal in order to attain equal K. E where m1>m2.
You are wrong. Velocities can not be equal in order to attain equal K. E where m1>m2.
Gaurav said:
1 decade ago
Consider m1 = 4, v1 = 2, m2 = 1, v2 = 4.
Here m1v1>m2v2 :).
Here m1v1>m2v2 :).
Ambarish said:
1 decade ago
1/2m1(v1)^2 = 1/2m2(v2)^2.
= m1(v1)^2 = m2(v2)^2.
= m1(v1)^2/m2(v2)^2 = 1.
= (v1)^2/(v2)^2 is greater than 1(science m1/m2 is greater than 1).
= v1^2is greater than v2^2.
= v1 is greater than v2.
So, m1v1 is greater than m2v2.
= m1(v1)^2 = m2(v2)^2.
= m1(v1)^2/m2(v2)^2 = 1.
= (v1)^2/(v2)^2 is greater than 1(science m1/m2 is greater than 1).
= v1^2is greater than v2^2.
= v1 is greater than v2.
So, m1v1 is greater than m2v2.
Harish said:
1 decade ago
@Suresh.
Given, K.E1 = K.E2, also m1>m2, K.E1 = 1/2m1v1^2, K.E2 = 1/2m2v2^2.
In order to get both the KE equal, their Velocity should be equal since m1>m2 (given). Therefore, Momentum, m1v1 > m2v2.
Given, K.E1 = K.E2, also m1>m2, K.E1 = 1/2m1v1^2, K.E2 = 1/2m2v2^2.
In order to get both the KE equal, their Velocity should be equal since m1>m2 (given). Therefore, Momentum, m1v1 > m2v2.
(1)
Deep said:
1 decade ago
1/2 m1 v1^2 = 1/2 m2 v2^2.
As m1>m2 So v2 must be >v1.
m1.v1/m2.v2=v2/v1 will have value greater than 1. So m1.v1>m2.v2.
As m1>m2 So v2 must be >v1.
m1.v1/m2.v2=v2/v1 will have value greater than 1. So m1.v1>m2.v2.
(1)
Suresh kumawat said:
1 decade ago
How can you say that v1 = v2.
(1)
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