Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 2 (Q.No. 22)
22.
A differential pulley block has larger and smaller diameters of 100 mm and 80 mm respectively. Its velocity ratio is
Discussion:
18 comments Page 2 of 2.
Vishal merat said:
9 years ago
VR = Two of larger diameter dividing to larger diameter minus smaller diameter.
(1)
Raghu said:
9 years ago
Clear solution. Thank you all.
Ch.Bhaskar said:
9 years ago
For differential pulley:
VR = 2D/(D-d).
= 2*100/(100 - 80).
= 10.
VR = 2D/(D-d).
= 2*100/(100 - 80).
= 10.
Mahesh said:
9 years ago
Good answers! Thank you all.
Rk singh said:
10 years ago
Velocity of second pulley is wD1-wd2/2.
Velocity of first pulley is wD1.
Now v1/v2 = wD1/(wD1-wd2/2) = 2D1/(D1-d2).
Velocity of first pulley is wD1.
Now v1/v2 = wD1/(wD1-wd2/2) = 2D1/(D1-d2).
Palash biswas said:
1 decade ago
Velocity ratio of pulley = 2D/D-d.
Vijay Kumar said:
1 decade ago
2D/D-d.
Let's put the values.
2*100/100-80.
200/20.
10.
Let's put the values.
2*100/100-80.
200/20.
10.
Mukesh Verma said:
1 decade ago
Because Velocity ratio of differential pulley is 2D/D-d.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers