Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 2 (Q.No. 22)
22.
A differential pulley block has larger and smaller diameters of 100 mm and 80 mm respectively. Its velocity ratio is
Discussion:
18 comments Page 1 of 2.
Rk singh said:
10 years ago
Velocity of second pulley is wD1-wd2/2.
Velocity of first pulley is wD1.
Now v1/v2 = wD1/(wD1-wd2/2) = 2D1/(D1-d2).
Velocity of first pulley is wD1.
Now v1/v2 = wD1/(wD1-wd2/2) = 2D1/(D1-d2).
Kudrat sharma said:
5 years ago
MA = 2D/D-d
VR = 1/MA for 100 percent efficiency.
It has an error as it should ask for MA.
VR = 1/MA for 100 percent efficiency.
It has an error as it should ask for MA.
Vishal merat said:
9 years ago
VR = Two of larger diameter dividing to larger diameter minus smaller diameter.
(1)
Balachandra Padiyar said:
8 years ago
VR=2D/D-d.
=2*100/(100-80),
=200/20,
=10,
So, the answer is B.
=2*100/(100-80),
=200/20,
=10,
So, the answer is B.
Ch.Bhaskar said:
9 years ago
For differential pulley:
VR = 2D/(D-d).
= 2*100/(100 - 80).
= 10.
VR = 2D/(D-d).
= 2*100/(100 - 80).
= 10.
Sharanagouda choudri said:
8 years ago
VR=2D/D-d.
=2*100/(100-80),
=200/20,
=10.
So, the answer is B.
=2*100/(100-80),
=200/20,
=10.
So, the answer is B.
(2)
Vijay Kumar said:
1 decade ago
2D/D-d.
Let's put the values.
2*100/100-80.
200/20.
10.
Let's put the values.
2*100/100-80.
200/20.
10.
Mukesh Verma said:
1 decade ago
Because Velocity ratio of differential pulley is 2D/D-d.
Bhanu said:
8 years ago
Thank you for giving the explanation of the solution.
Ranjit Kumar Behera said:
8 years ago
VR=2D/D-d.
=2*100/100-80
=200/20
=10(Ans).
=2*100/100-80
=200/20
=10(Ans).
(3)
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