Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 2 (Q.No. 22)
22.
A differential pulley block has larger and smaller diameters of 100 mm and 80 mm respectively. Its velocity ratio is
Discussion:
18 comments Page 1 of 2.
Ranjit Kumar Behera said:
8 years ago
VR=2D/D-d.
=2*100/100-80
=200/20
=10(Ans).
=2*100/100-80
=200/20
=10(Ans).
(3)
Prashant bhade said:
5 years ago
Thanks for the explanation.
(2)
Joshi said:
6 years ago
Thanks for explaining.
(2)
Sharanagouda choudri said:
8 years ago
VR=2D/D-d.
=2*100/(100-80),
=200/20,
=10.
So, the answer is B.
=2*100/(100-80),
=200/20,
=10.
So, the answer is B.
(2)
SUSHANTA KUMAR SAHOO said:
8 years ago
VR=2D/D-d.
VR=2*100/100-80,
VR=10.
VR=2*100/100-80,
VR=10.
(1)
Vishal merat said:
9 years ago
VR = Two of larger diameter dividing to larger diameter minus smaller diameter.
(1)
MD AASIM KABIR said:
8 years ago
Thank you for all the given explanation.
Rakshit said:
10 months ago
The velocity ratio of pulley = 2D/D-d.
Kudrat sharma said:
5 years ago
MA = 2D/D-d
VR = 1/MA for 100 percent efficiency.
It has an error as it should ask for MA.
VR = 1/MA for 100 percent efficiency.
It has an error as it should ask for MA.
Balachandra Padiyar said:
8 years ago
VR=2D/D-d.
=2*100/(100-80),
=200/20,
=10,
So, the answer is B.
=2*100/(100-80),
=200/20,
=10,
So, the answer is B.
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