Logical Reasoning - Number Series - Discussion
Discussion Forum : Number Series - Type 1 (Q.No. 12)
Directions to Solve
In each series, look for the degree and direction of change between the numbers. In other words, do the numbers increase or decrease, and by how much
12.
Look at this series: 14, 28, 20, 40, 32, 64, ... What number should come next?
Answer: Option
Explanation:
This is an alternating multiplication and subtracting series: First, multiply by 2 and then subtract 8.
Discussion:
85 comments Page 8 of 9.
Ram Karthick said:
10 years ago
1st no + with same = (Answer - 8).
14, 28 (14+14), (28-8) 20, 40 (20+20), (40-8) 32, 64 (32+32) = 56 (64-8).
14, 28 (14+14), (28-8) 20, 40 (20+20), (40-8) 32, 64 (32+32) = 56 (64-8).
Subhankar said:
10 years ago
First number*2 = Second number.
Second number-8 = Third number.
14*2=28.
28-8=20.
20*2=40.
40-8=32.
32*2=64.
64-8=56.
Second number-8 = Third number.
14*2=28.
28-8=20.
20*2=40.
40-8=32.
32*2=64.
64-8=56.
Yash said:
10 years ago
14+6=20.
20+8=28.
28+4=32.
32+8=40.
40+8=48.
48+8=56.
56+8=64.
20+8=28.
28+4=32.
32+8=40.
40+8=48.
48+8=56.
56+8=64.
Chalin said:
1 decade ago
14+14=28.
And then subtract 28-8=20.
20+20=40.
And subtract.
40-8=32.
And add above number.
32+32=64.
And now subtract.
64-8=56.
You get the answer 56.
And then subtract 28-8=20.
20+20=40.
And subtract.
40-8=32.
And add above number.
32+32=64.
And now subtract.
64-8=56.
You get the answer 56.
Gideon Brian said:
1 decade ago
I have this question: A series has 17 numbers, if the second is 3, what is the fast number?
P.Rajendran said:
2 decades ago
There is one more solution for the above ques..but the answer s not there in options. Try it. Check let us take alternate no's 14,20,32,?
14+6=20
20+(6*2)=32
32+{6*3)=50...ans.
For verification--
now we can able to see that each alternate no's are half to its next no.
14*2=28 so on..
therefore 50*2=100...{1}
now,
28+12=40
40+{12*2)=64
64+{12*3)=100....(2)
You got the answer.
14+6=20
20+(6*2)=32
32+{6*3)=50...ans.
For verification--
now we can able to see that each alternate no's are half to its next no.
14*2=28 so on..
therefore 50*2=100...{1}
now,
28+12=40
40+{12*2)=64
64+{12*3)=100....(2)
You got the answer.
Suraj said:
1 decade ago
14, 28(14*2), 20(14+6), 40(28+12), 32(20+12), 64(40+24), 56(32+24) + (24*2)112
Rs said:
1 decade ago
Look at the alternate series 14, 28, 20, 40, 32, 64
14-20 = -6 28-40 = 12.
20-32 = -12(Double of above) 40-64 = 24(Double of above).
So,
32-? =Double of above i.e. 12+12 = 24.
Answer is 32+24 = 56.
14-20 = -6 28-40 = 12.
20-32 = -12(Double of above) 40-64 = 24(Double of above).
So,
32-? =Double of above i.e. 12+12 = 24.
Answer is 32+24 = 56.
Prasanth said:
1 decade ago
Why can't we say the Answer D.
As it was Multiplied by 2 with each number and with last 64*2 can get 128.
As it was Multiplied by 2 with each number and with last 64*2 can get 128.
Amit said:
1 decade ago
Why we subtract? Its simple multiplication in sequence.
14*2 = 28.
20*2 = 40.
32*2 = 64.
64*2 = 128.
Answer 128.
14*2 = 28.
20*2 = 40.
32*2 = 64.
64*2 = 128.
Answer 128.
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