Logical Reasoning - Number Series - Discussion

14*2 = 28,28-8 = 20;
20*2 = 40,40-8 = 32;
32*2 = 64,64-8 = 56;

Answer is 56.

14*2 = 28.
28-8 = 20.
20*2 = 40.
40-8 = 32.
32*2 = 64.
64-8 = 56 easy method.

The 2 nos as one set 14, 28 , 20, 40, 32, 64..

So it can be divided as (7x2),(7x4),(10x2),(10x4),(16x2),(16x4)..

So now 7, 10, 16 fall a line.
And

7+3 = 10
10+6 (3x2)=16
16+12(6x2)=28

(or)  

7+3 (3x1) = 10
10+6(3x2) =16
16+9(3x3) =25

So the series may be either,

7, 10, 16, 28
or
7, 10, 16, 25

If we take the first series then we will get 28x2 = 56.

If we take the next series then we will get 25x2 = 50.

Both answers are correct but as we have only 56 as option here 56 is the right answer.

14+6=20
20+(6*2)=32
32+(12*2)=56

Like this:

28+12=40
40+(12*2)=64
64+(24*2)=112

We can also do it this way

14, 28 consider this as first set where the second number is twice as first number

20, 40 consider this as second set where the second number is twice as first number

32, 64 consider this as third set where the second number is twice as first number

Take the first number of each set 14, 20, 32 as A, B, C where B is A+6, C is B+12, so D would be C+24 and E would be D+48 and so on..

So, the next set would be 56, 112 and next to that would be 104, 208 and so on