Logical Reasoning - Number Series - Discussion

Discussion Forum : Number Series - Type 1 (Q.No. 12)
Directions to Solve
In each series, look for the degree and direction of change between the numbers. In other words, do the numbers increase or decrease, and by how much

12.
Look at this series: 14, 28, 20, 40, 32, 64, ... What number should come next?
52
56
96
128
Answer: Option
Explanation:
This is an alternating multiplication and subtracting series: First, multiply by 2 and then subtract 8.
Discussion:
87 comments Page 6 of 9.

Pravesh bansal said:   1 decade ago
If we see odd place of this series then we find every digit is increase by adding table of 6 like
14+6=20
20+12=32 now the ans is
32+18=50

So the right answer is 50.

Rohit.rcert said:   1 decade ago
Good one Question......P, rajendran is also right.

It's a series of number in which number is alternativaly changed by as usually +X and -8 and where X is jsut got number when it has a turn of +X to change series and then we use -8 and again we use +X which is the just got number by using -8.

Now we again using -8 and got a nuber and now we use +X where X is the just got number [normal like we are changing by +3 and -1.......only instead od fix 3 we have changable X that is changed in every step].

Rutvij said:   1 decade ago
50 is also a Right answer. This Series follows multiple patterns!

Dheeraj said:   1 decade ago
14 28 20 40 32 64

14+6=20
20+12=32
32+18=50

28+12=40
40+24=64
64+36=100

The answer should be 50 100, why 56 112???

Pundrik Vinayak said:   1 decade ago
14 28 20 40 32 64 56 112..


14*2=28 14+6=20 20*2=40 20+(12)=32 32*2=64

32+24=56 56*2=122..........

S.Balaji said:   1 decade ago
We can also do it this way

14, 28 consider this as first set where the second number is twice as first number

20, 40 consider this as second set where the second number is twice as first number

32, 64 consider this as third set where the second number is twice as first number

Take the first number of each set 14, 20, 32 as A, B, C where B is A+6, C is B+12, so D would be C+24 and E would be D+48 and so on..

So, the next set would be 56, 112 and next to that would be 104, 208 and so on

KTS said:   1 decade ago
One more answer is possible. 50
14 , 28(14x2) , 20(14+6), 40(20x2), 32(20+6x20) , 64(32x2), 50(32+6x3), 100(50x2)

Pavan said:   1 decade ago
@P.Rajendran..thought of the same thing but the ans isn't there in the options...

Nikhila said:   1 decade ago
Ya its ok with procedure. But why should we take the nums 2 and 8?

Vijender said:   2 decades ago
s1:14,20,32,n,n1.......
s2:2*14,2*20,2*32,m,m1
20-14=6*1
32-20=6*2
ans:
s1:
n=32+6*2*2=32+24=56


s2=s1*2
m=n*2=56*2=112

series:

s1:14,20,32,56,
s2:2*14,2*20,2*32,112,
series:
s2:14, 28, 20, 40, 32, 64, 56,112


Post your comments here:

Your comments will be displayed after verification.