Java Programming - Language Fundamentals - Discussion
Discussion Forum : Language Fundamentals - Finding the output (Q.No. 7)
7.
In the given program, how many lines of output will be produced?
public class Test
{
public static void main(String [] args)
{
int [] [] [] x = new int [3] [] [];
int i, j;
x[0] = new int[4][];
x[1] = new int[2][];
x[2] = new int[5][];
for (i = 0; i < x.length; i++)
{
for (j = 0; j < x[i].length; j++)
{
x[i][j] = new int [i + j + 1];
System.out.println("size = " + x[i][j].length);
}
}
}
}
Answer: Option
Explanation:
The loops use the array sizes (length).
It produces 11 lines of output as given below.
D:\Java>javac Test.java D:\Java>java Test size = 1 size = 2 size = 3 size = 4 size = 2 size = 3 size = 3 size = 4 size = 5 size = 6 size = 7
Therefore, 11 is the answer.
Discussion:
17 comments Page 1 of 2.
Sri said:
1 decade ago
As for the above declaration :
when the outer loop start to execute starts from 0, 1, 2 is the size of the 'x' 3 is size of x. And every x initializes inner loop with their sizes so, when outer loop starts execution x takes first argument at that time inner loop executes 4 times, after that jvm come out of inner loop and increment apply for outer loop at that time 'x' takes 1 and it will be executes 2 times...and same as 3 rd time.
As for coding
x[0] is i=0 it comes inner loop j=0.
and it returns[0+0+1].
i=0,j=1 it gives [0+1+1].
i=0,j=2 it gives [0+2+1].
i=0,j=3 it gives [0+3+1].
And the size of x[0] is only 4 .
So,loop comes inner loop again it increment.
i=1,j=0 it gives [1+0+1].
i=1,j=1 it gives [1+1+1].
And the size of x[1]is 2.
So,loop comes inner loop again it increment
i=2,j=0 it gives [2+0+1].
.
.
.
i=2,j=4 it gives [2+4+1]
Totally it executes 11 lines.
Please try to understand it.
when the outer loop start to execute starts from 0, 1, 2 is the size of the 'x' 3 is size of x. And every x initializes inner loop with their sizes so, when outer loop starts execution x takes first argument at that time inner loop executes 4 times, after that jvm come out of inner loop and increment apply for outer loop at that time 'x' takes 1 and it will be executes 2 times...and same as 3 rd time.
As for coding
x[0] is i=0 it comes inner loop j=0.
and it returns[0+0+1].
i=0,j=1 it gives [0+1+1].
i=0,j=2 it gives [0+2+1].
i=0,j=3 it gives [0+3+1].
And the size of x[0] is only 4 .
So,loop comes inner loop again it increment.
i=1,j=0 it gives [1+0+1].
i=1,j=1 it gives [1+1+1].
And the size of x[1]is 2.
So,loop comes inner loop again it increment
i=2,j=0 it gives [2+0+1].
.
.
.
i=2,j=4 it gives [2+4+1]
Totally it executes 11 lines.
Please try to understand it.
(1)
Gopal said:
1 decade ago
When i=0 then x[0].length=4 (given in the program that x[0] = new int[4][]).
Here j loop repeats 4 times.
When i=1 then x[1].length=2 (given in the program that x[1] = new int[2][]).
Here j loop repeats 2 times.
When i=2 then x[2].length=5 (given in the program that x[2] = new int[5][]).
Here j loop repeats 5 times.
Totally it executes 11 lines.
Here j loop repeats 4 times.
When i=1 then x[1].length=2 (given in the program that x[1] = new int[2][]).
Here j loop repeats 2 times.
When i=2 then x[2].length=5 (given in the program that x[2] = new int[5][]).
Here j loop repeats 5 times.
Totally it executes 11 lines.
(1)
Chidu said:
9 years ago
0th iteration->0 1 2 3;
1st iteration->0 1;
2ns iteration->0 1 2 3 4.
count total number in the right side,
So ans is 11.
1st iteration->0 1;
2ns iteration->0 1 2 3 4.
count total number in the right side,
So ans is 11.
(1)
HARSHAD said:
9 years ago
x[0] = new int[4][];
x[1] = new int[2][];
x[2] = new int[5][];
4+2+5=11.
x[1] = new int[2][];
x[2] = new int[5][];
4+2+5=11.
(1)
Hye Jung said:
10 years ago
Why is the second for loop executed first?
Srrivatsan Sekar said:
5 years ago
Yes, @abhijit.
Java allows 3D arrays. Because in java we have 1D and multi D arrays. In the case of multi-D arrays, we can have 2D and 3D arrays.
Java allows 3D arrays. Because in java we have 1D and multi D arrays. In the case of multi-D arrays, we can have 2D and 3D arrays.
Tanu said:
7 years ago
I guess the answer should be 9. It could have been 11 if the condition for the loops would be i/j<=x. Length().
Vicky said:
8 years ago
How the size of array becomes 4?
Logaa said:
9 years ago
Can anyone please explain that nested for loop operation in detail? please.
Rahul said:
10 years ago
Well explained @Sri.
@All.
Please check Sri's explanation to understand the answer.
@All.
Please check Sri's explanation to understand the answer.
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