Java Programming - Language Fundamentals
Exercise : Language Fundamentals - Finding the output
- Language Fundamentals - General Questions
- Language Fundamentals - Finding the output
6.
What will be the output of the program?
public class CommandArgsTwo
{
public static void main(String [] argh)
{
int x;
x = argh.length;
for (int y = 1; y <= x; y++)
{
System.out.print(" " + argh[y]);
}
}
}
and the command-line invocation is
> java CommandArgsTwo 1 2 3
Answer: Option
Explanation:
An exception is thrown because at some point in (System.out.print(" " + argh[y]);), the value of x will be equal to y, resulting in an attempt to access an index out of bounds for the array. Remember that you can access only as far as length - 1, so loop logical tests should use x < someArray.length as opposed to x < = someArray.length.
7.
In the given program, how many lines of output will be produced?
public class Test
{
public static void main(String [] args)
{
int [] [] [] x = new int [3] [] [];
int i, j;
x[0] = new int[4][];
x[1] = new int[2][];
x[2] = new int[5][];
for (i = 0; i < x.length; i++)
{
for (j = 0; j < x[i].length; j++)
{
x[i][j] = new int [i + j + 1];
System.out.println("size = " + x[i][j].length);
}
}
}
}
Answer: Option
Explanation:
The loops use the array sizes (length).
It produces 11 lines of output as given below.
D:\Java>javac Test.java D:\Java>java Test size = 1 size = 2 size = 3 size = 4 size = 2 size = 3 size = 3 size = 4 size = 5 size = 6 size = 7
Therefore, 11 is the answer.
8.
What will be the output of the program?
public class X
{
public static void main(String [] args)
{
String names [] = new String[5];
for (int x=0; x < args.length; x++)
names[x] = args[x];
System.out.println(names[2]);
}
}
and the command line invocation is
> java X a b
Answer: Option
Explanation:
The names array is initialized with five null elements. Then elements 0 and 1 are assigned the String values "a" and "b" respectively (the command-line arguments passed to main). Elements of names array 2, 3, and 4 remain unassigned, so they have a value of null.
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