General Knowledge - Chemistry - Discussion
Discussion Forum : Chemistry - Section 1 (Q.No. 68)
68.
The number of waves made by an electron moving in an orbit having maximum magnetic quantum number is +3
Discussion:
15 comments Page 1 of 2.
Muhammad Rizwan said:
5 years ago
No of waves mean no.of orbits( shells)
I.e when m=+_3 ( which is also equal to azimuthal qunatum number l=3)
As l= n- 1.
so;
n= l+ 1.
= 3+1=4.
I.e when m=+_3 ( which is also equal to azimuthal qunatum number l=3)
As l= n- 1.
so;
n= l+ 1.
= 3+1=4.
Shivam singh said:
6 years ago
Find the number of electron in shell 2nsquare so m = 2l+1 m=3.
L =1 now use n= l-1.
N = 2 put the 2*2*4 = 8 e so + electron in 4.
L =1 now use n= l-1.
N = 2 put the 2*2*4 = 8 e so + electron in 4.
Krishna said:
7 years ago
Thanks all.
Siva Rama Krishna said:
8 years ago
Thank you all.
Danish P R said:
8 years ago
The Answer is option A.
Himanshu said:
9 years ago
You are right @Archana.
Vijay said:
9 years ago
It is very easy 1s, 2s, 2p, 3s, 3p, 3d, 4s, 4p, 4d, 4f orbitals.
For 1st orbit only s orbital i.e. 0, for 2nd orbit s& p i.e. 0 for s, then1, 0, -1 for p, next for 3rd orbit, s, p, d orbitals.
i. e. for d, 2, 1, 0, -1, -2 and for 4th orbit, 4s, 4p, 4d, 4f orbitals. For f 3, 2, 1, 0, -1, -2, -3 that's all.
Chemistry is always the BEST.
For 1st orbit only s orbital i.e. 0, for 2nd orbit s& p i.e. 0 for s, then1, 0, -1 for p, next for 3rd orbit, s, p, d orbitals.
i. e. for d, 2, 1, 0, -1, -2 and for 4th orbit, 4s, 4p, 4d, 4f orbitals. For f 3, 2, 1, 0, -1, -2, -3 that's all.
Chemistry is always the BEST.
Ishdeep said:
9 years ago
Why can't the answer be any values greater than 3?
As here m=3, therefore, n can be 4, 5, 6 and so, on.
As here m=3, therefore, n can be 4, 5, 6 and so, on.
Archana said:
9 years ago
Value of m = 0, 1, 2, 3.
If m = 4 then n = 4 because they are four values of m.
If m = 4 then n = 4 because they are four values of m.
Puneet said:
9 years ago
I can't understand what is the concept of orientation.
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