General Knowledge - Chemistry - Discussion

The electron configurations are as follows:

1. **Fe²⁺ (Z = 26):** [Ar] 3d⁶.
=> The number of d-electrons is 6.

2. **Ne (Z = 10):** 1s² 2s² 2p⁶
=> There are no p-electrons in Ne.

3. **Mg (Z = 12):** 1s² 2s² 2p⁶ 3s²
=> The number of s-electrons is 2.

4. **Fe (Z = 26):** [Ar] 4s² 3d⁶
=> The number of d-electrons is 6.

5. **Cl (Z = 17):** 1s² 2s² 2p⁶ 3s² 3p⁵
=> The number of p-electrons is 5.

In summary:

- The number of d-electrons in Fe²⁺ (Z = 26) is **6**.
- The number of p-electrons in Ne (Z = 10) is **0**.
- The number of s-electrons in Mg (Z = 12) is **2**.
- The number of d-electrons in Fe (Z = 26) is **6**.
- The number of p-electrons in Cl (Z = 17) is **5**.

Therefore, the statement is correct.

The number of d-electrons in Fe²⁺ is not equal to the specified electron counts in Ne, Mg, Fe, and Cl.

Fe (Z=26) configuration is [Ar]18 4S2,3d6.

Fe2+ means it will lose two electrons from its outer shell which is 4S.

So the configuration is [Ar]18 4s0, 3d6 . here the Fe2+ is stable because orbitals are fully filled or fully empty. d-electrons Numbers are 6.

Ne10 configuration is 1S2,2S2,2p6. p-electrons Numbers are 6
Mg12 configuration is 4s2,2s2,2p6,3s2 so s-electrons Numbers are 6
Cl17 configuration is 4s2,2s2,2p6,3s2,4p5. After applying half filled orbitals rule, the configuration will be 4s2,2s2,2p6,3s1,3p6 so p-electrons Numbers are 12
So, D is the correct answer.

The electron configuration of Fe+2 will be [Ar]4S13d5.

Please give the correct answer description.

Thanks all for explaining the answer.

But I think the question is incorrect, as it asked.

It should be, The number of d-electrons in Fe2+ (Z = 26) is equal to that of.

I think option C is right.

Since outer most electron that is in the d orbital there number are 10 and also Fe2+ (Z=26) that's outer most electron numbers are 10 in d orbital.

Answer must be option C) Fe (26).

I think the answer is B because, when its Mg=12, it is 1s2 2s2 2p6 3S2 but the Fe=26 is 1s2 2s2 2p6 3s2 3p6 4s2 3D6.

Even after you lose one electron from the 'd' of Fe orbital it still is not equal to that of Mg.

I think the answer is correct because after D, orbital looses their one electron it stabilised fully.