General Knowledge - Chemistry - Discussion

Discussion Forum : Chemistry - Section 1 (Q.No. 69)
69.
The number of atoms present in 21.6 gram of silver (atomic weight = 108) are same as the molecules in
1.8 gram of H2O
12 moles of KMnO4
0.6N H2SO4
4.6 gram of C2H5OH
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
19 comments Page 1 of 2.

Ani said:   1 decade ago
Please explain.

Jainnandish said:   1 decade ago
108.0 gm of silver = 1 atom of silver.

21.6 gm of silver = 21.6/108 =0.02.

Dhruvil said:   1 decade ago
Answer is A: As moles of silver (21.6/108) = 0.2 and moles of water is also (1.8/18) = 0.1.

So H2O Dissociates into [H+] and [OH-]. So it has two hydrogen ion that can accept an electron [H+] and one that can donate an electron [OH-] when Ag is in its ionic form i.e. Ag+.

Vishawkirti said:   1 decade ago
Moles of silver = 0.2.

Atoms of silver = 1.2044*10 raise to the power 23.

Moles of water = 0.110.

Atoms = 1.088*10 raise to the power 23.

Correct answer is (A).
(1)

Divya said:   10 years ago
Why Atoms of Silver = 1.2044*10 raise to the power 23.

Atoms of Water = 1.088*10 raise to the power 23.

Can you please explain?

Abhas said:   10 years ago
@Divya.

Atoms of silver = Given no. of moles*6.023x10^23.

= 0.2*6.023x10^23.

= 1.2044x10^23.

Jahan said:   10 years ago
Confused with the answer. Can anyone explain again please?

Kingsley said:   10 years ago
So what's the correct answer?

Sreenish c k said:   9 years ago
Which answer is correct?

Shakthi said:   9 years ago
No of atoms = moles * Avogadro no.

So, Option A is correct.


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