Engineering Mechanics - Moments of Inertia - Discussion

Discussion :: Moments of Inertia - General Questions (Q.No.2)

2. 

Determine the inertia of the parabolic area about the x axis.

[A]. Ix = 11,430 in.4
[B]. Ix = 32,800 in.4
[C]. Ix = 13,330 in.4
[D]. Ix = 21,300 in.4

Answer: Option A

Explanation:

No answer description available for this question.

Dhinesh said: (May 26, 2011)  
Give answer descripition.

G.Vasu From Iiit(Rkvalley) said: (Mar 6, 2012)  
dIx=y^2.dA
where dA=x.dy
40.y=x^2
=>x=square root of(40.y)
then, susbstitute the above values in main equation
dIx=y^2.over root of(40.y).dy
then take integral on both side from 0 to 10.
then you get Ix=11,430 in^4.

Aksharkumar said: (Oct 28, 2013)  
Determine the moment of inertia for section about horizontal and vertical centroidal 120.

Vio said: (Sep 25, 2014)  
dIx = y^2.dA.
Where dA = x.dy.
40.y = x^2.
=> x=square root of(40.y).

Then, susbstitute the above values in main equation,
dIx = y^2.over root of(40.y).dy.

Then take integral on both side from 0 to 10.
Then you get Ix=11,430 in^4.

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