### Discussion :: Moments of Inertia - General Questions (Q.No.2)

Dhinesh said: (May 26, 2011) | |

Give answer descripition. |

G.Vasu From Iiit(Rkvalley) said: (Mar 6, 2012) | |

dIx=y^2.dA where dA=x.dy 40.y=x^2 =>x=square root of(40.y) then, susbstitute the above values in main equation dIx=y^2.over root of(40.y).dy then take integral on both side from 0 to 10. then you get Ix=11,430 in^4. |

Aksharkumar said: (Oct 28, 2013) | |

Determine the moment of inertia for section about horizontal and vertical centroidal 120. |

Vio said: (Sep 25, 2014) | |

dIx = y^2.dA. Where dA = x.dy. 40.y = x^2. => x=square root of(40.y). Then, susbstitute the above values in main equation, dIx = y^2.over root of(40.y).dy. Then take integral on both side from 0 to 10. Then you get Ix=11,430 in^4. |

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