Discussion :: Moments of Inertia - General Questions (Q.No.2)
Determine the inertia of the parabolic area about the x axis.
Answer: Option A
No answer description available for this question.
|Dhinesh said: (May 26, 2011)|
|Give answer descripition.|
|G.Vasu From Iiit(Rkvalley) said: (Mar 6, 2012)|
=>x=square root of(40.y)
then, susbstitute the above values in main equation
dIx=y^2.over root of(40.y).dy
then take integral on both side from 0 to 10.
then you get Ix=11,430 in^4.
|Aksharkumar said: (Oct 28, 2013)|
|Determine the moment of inertia for section about horizontal and vertical centroidal 120.|
|Vio said: (Sep 25, 2014)|
|dIx = y^2.dA.
Where dA = x.dy.
40.y = x^2.
=> x=square root of(40.y).
Then, susbstitute the above values in main equation,
dIx = y^2.over root of(40.y).dy.
Then take integral on both side from 0 to 10.
Then you get Ix=11,430 in^4.
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