Engineering Mechanics - KOP: Impulse and Momentum

Exercise : KOP: Impulse and Momentum - General Questions
  • KOP: Impulse and Momentum - General Questions
1.

A golf ball having a mass of 40 g is struck such that it has an initial velocity of 200 m/s as shown. Determine the horizontal and vertical components of the impulse given to the ball.

Impx = 4.00 N-s, Impy = 6.93 N-s
Impx = 6.93 N-s, Impy = 4.00 N-s
Impx = 6.93 N-s, Impy = 4.39 N-s
Impx = 4.00 N-s, Impy = 7.32 N-s
Answer: Option
Explanation:
No answer description is available. Let's discuss.

2.

The drop hammer H has a weight of 900 lb and falls from rest. H has a weight of 900 lb and falls from rest h = 3 ft onto a forged anvil plate P that has a weight of 500 lb. The plate is mounted on a set of springs which have a combined stiffness of kT = 500 lb/ft. Determine (a) the velocity of P and H just after collision and (b) the maximum compression in the springs caused by the impact. The coefficient of restitution between the hammer and the plate is e = 0.6. Neglect friction along the vertical guide posts A and B.

vH2 = 3.97 ft/s, vP2 = 17.87 ft/s, x = 4.15 ft
vH2 = 8.94 ft/s, vP2 = 8.94 ft/s, x = 2.57 ft
vH2 = 5.96 ft/s, vP2 = 14.30 ft/s, x = 3.52 ft
vH2 = 20.8 ft/s, vP2 = 12.51 ft/s, x = 3.20 ft
Answer: Option
Explanation:
No answer description is available. Let's discuss.

3.

A basket and its contents weigh 10 lb. A 20-lb monkey grabs the other end of the rope and very quickly (almost instantaneously) accelerates by pulling hard on the rope until he is moving with a constant speed of vm/r = 2 ft/s measured relative to the rope. The monkey then continues climbing at this constant rate relative to the rope for 3 seconds. How fast is the basket rising at the end of the 3 seconds? Neglect the mass of the pulley and the rope.

vbasket = 33.5 ft/s
vbasket = 32.2 ft/s
vbasket = 96.6 ft/s
vbasket = 97.9 ft/s
Answer: Option
Explanation:
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4.

In cases of emergency, the gas actuator can be used to move a 75-kg block B by exploding a charge C near a pressurized cylinder of negligible mass. As a result of the explosion, the cylinder fractures and the released gas forces the front part ofthe cylinder, A, to move B and the floor is = 0.5, determine the impulse that the actuator must impart to B.

Imp = 147.2 N-s
Imp = 132.2 N-s
Imp = 15.00 N-s
Imp = 162.2 N-s
Answer: Option
Explanation:
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5.

Two coins A and B have the initial velocities shown just before they collide at point O. If they have weights of WA = 13.2(10-3) lb and WB = 6.6(10-3) lb and the surface upon which they slide is smooth, determine their speed just after impact. The coefficient of restitution is e = 0.65.

vA2 = 1.856 ft/s, vB2 = 3.18 ft/s
vA2 = 1.871 ft/s, vB2 = 2.76 ft/s
vA2 = 1.772 ft/s, vB2 = 2.88 ft/s
vA2 = 1.755 ft/s, vB2 = 2.92 ft/s
Answer: Option
Explanation:
No answer description is available. Let's discuss.