Engineering Mechanics - KOP: Impulse and Momentum - Discussion

Discussion :: KOP: Impulse and Momentum - General Questions (Q.No.1)


A golf ball having a mass of 40 g is struck such that it has an initial velocity of 200 m/s as shown. Determine the horizontal and vertical components of the impulse given to the ball.

[A]. Impx = 4.00 N-s, Impy = 6.93 N-s
[B]. Impx = 6.93 N-s, Impy = 4.00 N-s
[C]. Impx = 6.93 N-s, Impy = 4.39 N-s
[D]. Impx = 4.00 N-s, Impy = 7.32 N-s

Answer: Option B


No answer description available for this question.

Dhananjay said: (Sep 16, 2011)  
Please give the solution.

Mithun said: (Dec 2, 2015)  
Impulse = Force*Time.

Rameez said: (Apr 8, 2016)  
I need answer and explanation.

Kavya said: (Nov 23, 2016)  
Please give the solution.

Deba said: (Dec 6, 2016)  
I need answer with explanation. Please help me.

Aakanksha Patekar said: (Mar 2, 2017)  
Please explain the answer with correct explanation.

Srikanth said: (Aug 23, 2019)  
Please explain it in detail.

Nathan said: (Jan 19, 2021)  
Components of impulse
Since mu=impulse then let's find the components of u.
The angle is 90-60=30.


Components of Uy=200sin30.

So the impulses respectively is 173.2*0.04.
= 6.928Ns.

And the vertical is 100*0.04,

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