Engineering Mechanics - KOP: Impulse and Momentum - Discussion
Discussion Forum : KOP: Impulse and Momentum - General Questions (Q.No. 1)
1.
A golf ball having a mass of 40 g is struck such that it has an initial velocity of 200 m/s as shown. Determine the horizontal and vertical components of the impulse given to the ball.
Discussion:
8 comments Page 1 of 1.
Nathan said:
5 years ago
Components of impulse
Since mu=impulse then let's find the components of u.
The angle is 90-60=30.
Ux=200cos30,
=173.2m/s.
Components of Uy=200sin30.
=100m/s.
So the impulses respectively is 173.2*0.04.
= 6.928Ns.
And the vertical is 100*0.04,
=4Ns.
Since mu=impulse then let's find the components of u.
The angle is 90-60=30.
Ux=200cos30,
=173.2m/s.
Components of Uy=200sin30.
=100m/s.
So the impulses respectively is 173.2*0.04.
= 6.928Ns.
And the vertical is 100*0.04,
=4Ns.
Srikanth said:
6 years ago
Please explain it in detail.
Aakanksha patekar said:
9 years ago
Please explain the answer with correct explanation.
Deba said:
9 years ago
I need answer with explanation. Please help me.
Kavya said:
9 years ago
Please give the solution.
Rameez said:
9 years ago
I need answer and explanation.
Mithun said:
10 years ago
Impulse = Force*Time.
Dhananjay said:
1 decade ago
Please give the solution.
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