Engineering Mechanics - Kinematics of Particle (KOP) - Discussion
Discussion Forum : Kinematics of Particle (KOP) - General Questions (Q.No. 7)
7.
The v-s graph for a rocket sled is shown. Determine the acceleration of the sled when s = 100 m and s = 175 m.
Discussion:
4 comments Page 1 of 1.
Raj Shah said:
5 years ago
Let s0=0m, s1=150m, s2=200m, s3=100m, & s4=175m.
a3=[(s3-s0)/(s1-s0)]*v1*[(v1-v0)/(s1-s0)].
a3=11.11m/s*s.
a4=[(s4-s1)/(s2-s1)]*v1*[(v2-v1)/(s2-s1)].
a4= -25 m/s*s.
a3=[(s3-s0)/(s1-s0)]*v1*[(v1-v0)/(s1-s0)].
a3=11.11m/s*s.
a4=[(s4-s1)/(s2-s1)]*v1*[(v2-v1)/(s2-s1)].
a4= -25 m/s*s.
(1)
Pradeep said:
8 years ago
@Nayan it is a concept of the similar triangle:
which implies 150/50=100/v.
Gives v=100/3 and from s=v*t we will get t.
which implies 150/50=100/v.
Gives v=100/3 and from s=v*t we will get t.
Nayan said:
9 years ago
Please explain how you taking values of t and v?
RAJKIRAN HATHESHWAR said:
10 years ago
Step 1 - By similar triangle at s=100m, we will get v=(100/3)m/s.
Now from s=d/t; find t=3 sec.
Then from v=u+at, we will get a=11.11 m/s*s (here u=0).
Step 2 - Similarly at s=175m, v=25m/s and t=1sec. So that a=-25m/s*s.
Note:- in 2nd case you will not be 0, here you will be 50m/s.
THANK YOU.
Now from s=d/t; find t=3 sec.
Then from v=u+at, we will get a=11.11 m/s*s (here u=0).
Step 2 - Similarly at s=175m, v=25m/s and t=1sec. So that a=-25m/s*s.
Note:- in 2nd case you will not be 0, here you will be 50m/s.
THANK YOU.
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