Discussion :: Kinematics of Particle (KOP) - General Questions (Q.No.7)
|Rajkiran Hatheshwar said: (Dec 6, 2015)|
|Step 1 - By similar triangle at s=100m, we will get v=(100/3)m/s.
Now from s=d/t; find t=3 sec.
Then from v=u+at, we will get a=11.11 m/s*s (here u=0).
Step 2 - Similarly at s=175m, v=25m/s and t=1sec. So that a=-25m/s*s.
Note:- in 2nd case you will not be 0, here you will be 50m/s.
|Nayan said: (Feb 1, 2017)|
|Please explain how you taking values of t and v?|
|Pradeep said: (Feb 27, 2018)|
|@Nayan it is a concept of the similar triangle:
which implies 150/50=100/v.
Gives v=100/3 and from s=v*t we will get t.
|Raj Shah said: (Nov 25, 2020)|
|Let s0=0m, s1=150m, s2=200m, s3=100m, & s4=175m.
a4= -25 m/s*s.
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