Engineering Mechanics - General Principles - Discussion

Discussion Forum : General Principles - General Questions (Q.No. 1)
1.
Solve the following equation for the two roots of x:   x2 — 16 = 0
x = 2i,   –2i
x = 4i,   –4i
x = 4,   –4
x = 2,   –2
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
27 comments Page 2 of 3.

Cherry said:   1 decade ago
x^2 - 16 = 0
x^2 = 16
x = sqrt(16)
x = 4 or -4

Santhosh said:   1 decade ago
Billa's method is easiest and understandable.

Adil said:   1 decade ago
(x)2-(4)2=0
(x-4)(x+4)=0
x-4=0,x+4=0
x=4,x=-4

ARUN said:   9 years ago
Your method is easy to solve. @Naveen.
(1)

Rupa said:   10 years ago
X^2 - 16 = 0.

X^2 = 16.

X = 4, -4.
(1)

ASHOK.L.B.NAIK said:   1 decade ago
@Naveen's method is easy to solve.

Winfred said:   9 years ago
@All, Nice solution thanks for it.
(1)

Murali said:   1 decade ago
X^2-16=0.

X=sqrt (16).

X=4, -4.

Sri said:   1 decade ago
Well billa's method is also good.

Damodaran said:   1 decade ago
Well the three methods are good.


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