Engineering Mechanics - General Principles - Discussion
Discussion Forum : General Principles - General Questions (Q.No. 1)
1.
Solve the following equation for the two roots of x: x2 — 16 = 0
Discussion:
27 comments Page 1 of 3.
Ajmal k said:
7 years ago
X^2-16=0.
X= +/-(√16),
X= +/-(4),
X=(+4) & x=(-4).
X= +/-(√16),
X= +/-(4),
X=(+4) & x=(-4).
(1)
Darshan Dodia said:
8 years ago
According to Quadratic Equation ax^2+bx+c=0, roots of equation x = (-b+/-sqrt(b^2-4ac))/(2a).
(1)
Winfred said:
9 years ago
@All, Nice solution thanks for it.
(1)
ARUN said:
9 years ago
Your method is easy to solve. @Naveen.
(1)
Rupa said:
10 years ago
X^2 - 16 = 0.
X^2 = 16.
X = 4, -4.
X^2 = 16.
X = 4, -4.
(1)
Rakesh said:
1 decade ago
(x)2-16 = 0.
We know that a2-b2 = (a+b)(a-b).
(x)2-(4)2 = 0.
(x+4)(x-4) = 0.
x = -4, +4.
We know that a2-b2 = (a+b)(a-b).
(x)2-(4)2 = 0.
(x+4)(x-4) = 0.
x = -4, +4.
Cherry said:
1 decade ago
x^2 - 16 = 0
x^2 = 16
x = sqrt(16)
x = 4 or -4
x^2 = 16
x = sqrt(16)
x = 4 or -4
Kamal said:
1 decade ago
Why do use iota. Ioti (i) its value is also -1. That answer is also right option b.
Murali said:
1 decade ago
X^2-16=0.
X=sqrt (16).
X=4, -4.
X=sqrt (16).
X=4, -4.
Raja said:
1 decade ago
Billa's method is very easy.
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