# Engineering Mechanics - General Principles - Discussion

### Discussion :: General Principles - General Questions (Q.No.1)

1.

Solve the following equation for the two roots of x:   x2 — 16 = 0

 [A]. x = 2i,   –2i [B]. x = 4i,   –4i [C]. x = 4,   –4 [D]. x = 2,   –2

Explanation:

No answer description available for this question.

 Naveen said: (Dec 10, 2010) x^2-16=0 (x-4)*(x+4)=0 (x-4)=0 or (x+4)=0 x=4 , -4

 Billa said: (Jan 28, 2011) x^2 - 16 = 0 x^2 = 16 x = sqrt(16) x = 4 or -4

 Prabu said: (Feb 25, 2011) Well Naveen you gave the exact method to find the ans.

 Nishita said: (Apr 28, 2011) (x^2-16)=0 (x^2-4^2)=0 (x-4)(x+4)=0 therefore, (x-4)=0,x=4 (x+4)=0,x=-4 hence,x=4,-4

 Lakshmi said: (Jun 3, 2011) x^2 = 16 x = sqrt(16) Therefore, x = +4 or -4.

 Balajikumar said: (Jun 23, 2011) LAKSHMI Method is best one

 Sri said: (Jul 8, 2011) Well billa's method is also good.

 Kamal said: (Jul 16, 2011) Naveen is absolutely correct!!

 Damodaran said: (Aug 13, 2011) Well the three methods are good.

 Ashok said: (Aug 22, 2011) x^2-16=0 x^2=16 x=sq.root 16 i.e.x=+ or - 4 x=4;x=-4

 Adil said: (Sep 5, 2011) (x)2-(4)2=0 (x-4)(x+4)=0 x-4=0,x+4=0 x=4,x=-4

 James said: (Sep 26, 2011) Laxmi's method is good.

 Manik said: (Nov 2, 2011) Answer is correct.

 Ashok.L.B.Naik said: (Feb 8, 2012) @Naveen's method is easy to solve.

 Santhosh said: (Feb 24, 2012) Billa's method is easiest and understandable.

 Pravi said: (Mar 8, 2012) Laxi method is easy.

 Raja said: (May 23, 2012) Billa's method is very easy.

 Murali said: (Jun 28, 2012) X^2-16=0. X=sqrt (16). X=4, -4.

 Kamal said: (Sep 16, 2012) Why do use iota. Ioti (i) its value is also -1. That answer is also right option b.

 Cherry said: (Sep 25, 2012) x^2 - 16 = 0 x^2 = 16 x = sqrt(16) x = 4 or -4

 Rakesh said: (Jan 31, 2015) (x)2-16 = 0. We know that a2-b2 = (a+b)(a-b). (x)2-(4)2 = 0. (x+4)(x-4) = 0. x = -4, +4.

 Rupa said: (Jan 27, 2016) X^2 - 16 = 0. X^2 = 16. X = 4, -4.

 Arun said: (Jul 22, 2016) Your method is easy to solve. @Naveen.

 Winfred said: (Nov 13, 2016) @All, Nice solution thanks for it.

 Darshan Dodia said: (Jul 5, 2017) According to Quadratic Equation ax^2+bx+c=0, roots of equation x = (-b+/-sqrt(b^2-4ac))/(2a).

 Ajmal K said: (Nov 12, 2018) X^2-16=0. X= +/-(√16), X= +/-(4), X=(+4) & x=(-4).