Engineering Mechanics - General Principles - Discussion
Discussion Forum : General Principles - General Questions (Q.No. 1)
1.
Solve the following equation for the two roots of x: x2 — 16 = 0
Discussion:
27 comments Page 1 of 3.
Naveen said:
1 decade ago
x^2-16=0
(x-4)*(x+4)=0
(x-4)=0 or (x+4)=0
x=4 , -4
(x-4)*(x+4)=0
(x-4)=0 or (x+4)=0
x=4 , -4
Billa said:
1 decade ago
x^2 - 16 = 0
x^2 = 16
x = sqrt(16)
x = 4 or -4
x^2 = 16
x = sqrt(16)
x = 4 or -4
Prabu said:
1 decade ago
Well Naveen you gave the exact method to find the ans.
Nishita said:
1 decade ago
(x^2-16)=0
(x^2-4^2)=0
(x-4)(x+4)=0
therefore,
(x-4)=0,x=4
(x+4)=0,x=-4
hence,x=4,-4
(x^2-4^2)=0
(x-4)(x+4)=0
therefore,
(x-4)=0,x=4
(x+4)=0,x=-4
hence,x=4,-4
Lakshmi said:
1 decade ago
x^2 = 16
x = sqrt(16)
Therefore, x = +4 or -4.
x = sqrt(16)
Therefore, x = +4 or -4.
BALAJIKUMAR said:
1 decade ago
LAKSHMI Method is best one
Sri said:
1 decade ago
Well billa's method is also good.
Kamal said:
1 decade ago
Naveen is absolutely correct!!
Damodaran said:
1 decade ago
Well the three methods are good.
ASHOK said:
1 decade ago
x^2-16=0
x^2=16
x=sq.root 16
i.e.x=+ or - 4
x=4;x=-4
x^2=16
x=sq.root 16
i.e.x=+ or - 4
x=4;x=-4
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