Engineering Mechanics - Force Vectors
Exercise : Force Vectors - General Questions
- Force Vectors - General Questions
1.
The cord is attached between two walls. If it is 8 m long, determine the distance x to the point of attachment at B.
2.
Determine the magnitude of the resultant force by adding the rectangular components of the three forces.
3.
Express force F as a Cartesian vector; then determine its direction angles.
F = (-2i +j+2k) kN, 
= 48.2°, 
= 70.5°, 
= 48.2°
= 48.2°, = 70.5°, = 48.2°F = (-2i +j+2k) kN, = 131.8°, = 70.5°, = 48.2°
= 131.8°, = 70.5°, = 48.2°F = (-4i +j+4k) kN, = 48.2°, = 70.5°, = 48.2°
= 48.2°, = 70.5°, = 48.2°F = (-4i +2j+4k) kN, = 131.8°, = 70.5°, = 48.2°
= 131.8°, = 70.5°, = 48.2°4.
Determine the magnitude and direction of the resultant force.
R = 80.3 lb, 
= 106.2° CCW
= 106.2° CCWR = 80.3 lb, = 73.8° CCW
= 73.8° CCWR = 72.1 lb, = 63.6° CCW
= 63.6° CCWR = 72.1 lb, = 116.4° CCW
= 116.4° CCW5.
Force F acts on peg A such that one of its components, lying in the x-y plane, has a magnitude of 50 lb. Express F as a Cartesian vector.
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