Discussion :: Force Vectors - General Questions (Q.No.5)
|Aimen said: (Nov 28, 2014)|
|Please give me the solution.|
|Riyaz Ibrahim said: (Oct 8, 2015)|
|Go through F = 50sin60-50cos60+50tan60.|
|Ameet Kumar said: (Feb 16, 2016)|
|Kindly sir please give me the specific solution?|
|Gershom Ntsako said: (Mar 18, 2016)|
|50 = Fcos30.
F = 57.74.
57.74sin(30) = Z-COMPONENT.
THEREFORE x-component should be +ve and y-component will be -ve.
|Manoj said: (Feb 28, 2017)|
|We know that x component of the force F is F(x) = Fcos30.
From that F = F(x)/cos30= 57.77
From the figure, we come to know that the direction of the force is in +ve x direction -ve y direction and +ve z direction.
Then take the two options which have negative j.
Ffind z component F(y)k= Fcos60 z = 57.7*cos60=28.86k.
Hence Option D is correct.
|Anonymous said: (Nov 3, 2019)|
|How come everyone see 30 degree? I only see 60 degree only.|
|Anonymous said: (Feb 13, 2020)|
|See, F is making 60 degrees with the z-axis, but the question says "one of its components lying in the XY axis has a magnitude of 50". Therefore, we consider F making 30 degrees with X-axis (90-60 = 30) which gives => 50 = FCos30.|
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