Engineering Mechanics - Force Vectors - Discussion
Discussion Forum : Force Vectors - General Questions (Q.No. 1)
1.
The cord is attached between two walls. If it is 8 m long, determine the distance x to the point of attachment at B.
Discussion:
13 comments Page 1 of 2.
Kunal said:
7 years ago
8^2=1^2+2^2+x^2.
x^2=59,
x = 7.68,
x^2=59,
x = 7.68,
Prahlad said:
8 years ago
2^2-8^2-1^2=59 ,
Then √59=7.68.
Then √59=7.68.
Alex said:
8 years ago
Please, can anyone make it clear?
Susheel said:
10 years ago
More explain.
(1)
Nicky said:
10 years ago
Please explain it into details.
(1)
Karthi said:
10 years ago
Sir I cannot understand so please explain.
(1)
ABDUL KHALEQAUE said:
10 years ago
Suppose B point at black wall and A point at white wall. Draw a line perpendicular to white wall. Now apply Pythagoras formula. You will find square root of (8^2-(4-2)^2) = 7.7459.
It will give you hypotenuse of new triangle. Again apply same formula square root of (7.7459^2-1^2) = 7.68.
It will give you hypotenuse of new triangle. Again apply same formula square root of (7.7459^2-1^2) = 7.68.
(1)
Woxiiii said:
10 years ago
It's 3D Pythagoras so all you have to do is substitute into the formula a^2+b^2+c^2=d^2.
(1)
Riyaz Ibrahim said:
10 years ago
I am not satisfied, try to solve in simple format.
Second Right said:
1 decade ago
I agree with Mr. Right, there are two perpendicular right triangles that you must solve. This is an engineering mechanics question, not a grade 10 trigonometry question. The answer is x=sqrt(59).
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