Discussion :: Force Vectors - General Questions (Q.No.3)
|Ramesh said: (Mar 12, 2012)|
|I want the explaination. I can't understand.|
|Benjamin said: (Apr 7, 2012)|
|I am relearning a lot of maths and if there is anyone about that can write an method I would be very greatful, forgotten how this format works entirely.|
|Avinash said: (Jun 19, 2012)|
|Write the position vectors B and A. Then do A-B. Result is the vector direction.|
|Wahid said: (Jun 6, 2014)|
|A(4;1;-2) & B(0;3;2) then vect(AB) = 2(-2i+j+2k)and,
180-cos(a) = 2/AB then a = 131.8.
cos(b) = 1/AB then b = 70.5.
cos(c) = 2/AB then c = 48.2.
|.Shinde Mahesh said: (Jan 13, 2015)|
|I thing its very lengthy process. Any one can give shortcuts for this problem?|
|D Sanjog Roshan said: (Sep 9, 2017)|
|A(4,1,-2) and B(0,3,2).
Position vector, Rab=-4i+2j+4k
Unit vector of Rab=-4/6i+2/6j+4/6k
F=3(Rab)= option B.
|Hazim Khaleel said: (Jun 9, 2019)|
|The right answer is D.|
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