Engineering Mechanics - Equilibrium of a Particle

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Exercise :: Equilibrium of a Particle - General Questions

  • Equilibrium of a Particle - General Questions
1. 

The joint O of a space frame is subjected to four forces. Strut OA lies in the x-y plane and strut OB lies in the y-z plane. Determine the force acting in each if the three struts required for equilibrium of the joint. Set = 45°.

A. F = 46.4 lb, R = 400 lb, P = 424 lb
B. F = 566 lb, R = 424 lb, P = 1000 lb
C. F = 11.3 lb, R = 424 lb, P = 577 lb
D. F = 1166 lb, R = 424 lb, P = 1000 lb

Answer: Option B

Explanation:

No answer description available for this question. Let us discuss.

2. 

A "scale" is constructed with a 4-ft-long cord and the 10-lb block D. The cord is fixed to a pin at A and passes over two small pulleys at B and C. Determine the weight of the suspended block E if the system is in equilibrium when s = 1.5 ft.

A. W = 8.01 lb
B. W = 14.91 lb
C. W = 17.63 lb
D. W = 18.33 lb

Answer: Option D

Explanation:

No answer description available for this question. Let us discuss.

3. 

Determine the magnitudes ofthe forces P, R, and F required for equillibrium of point O.

A. R = 238 N, F = 181.0 N, P = 395 N
B. R = 1340 N, F = 740 N, P = 538 N
C. R = 419 N, F = 181.0 N, P = 395 N
D. R = 409 N, F = 504 N, P = 1099 N

Answer: Option D

Explanation:

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4. 

Determine the magnitude and direction of the resultant force FAB exerted along link AB by the tractive apparatus shown. The suspended mass is 10 kg. Neglect the size of the pulley at A.

A. FAB = 170.0 N, = 75.0°
B. FAB = 170.0 N, = 15.0°
C. FAB = 98.1 N, = 75.0°
D. FAB = 98.1 N, = 15.0°

Answer: Option D

Explanation:

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5. 

Determine the tension developed in cables OD and OB and the strut OC, required to support the 500-lb crate. The spring OA has an unstretched length of 0.2 ft and a stiffness of kOA = 350lb/ft. The force in the strut acts along the axis of the strut.

A. Fob = 289 lb, Foc = 175.0 lb, Fod = 131.3 lb
B. Fob = 86.2 lb, Foc = 175.0 lb, Fod = 506 lb
C. Fob = 375 lb, Foc = 0, Fod = 375 lb
D. Fob = 664 lb, Foc = 175.0 lb, Fod = 244 lb

Answer: Option B

Explanation:

No answer description available for this question. Let us discuss.