### Discussion :: Equilibrium of a Particle - General Questions (Q.No.4)

Pratik/Satish India said: (Aug 28, 2011) | |

Applying Lami's theorem , angle between horizontal plane and Link AB is 15 degree and again by lami's theorem Reaction AB is 10Kg i.e. 98.1 N. 10/Sin(105+θ)= 10/sin(135-θ) so θ= 15 Now 10/Sin(105+θ) = Fab/sin(120) So Fab = 10 Kg = 9.81*10 Kg = 98.1 N. |

P.Velmurugan said: (Sep 30, 2011) | |

Five forces of 100,200,300,400,and 500Nare acting at angles of 40deg,100 deg,210deg,280 deg,and 340 degin anticlockwise direction from the X-axis at a point ,all acting away from the point. Find the resultant force in magnitude and direction. |

P.Velmurugan said: (Sep 30, 2011) | |

Determine analytically the resultant of the coplanar forces acting vertically- upwards.1)40N 2)20N at 30CM 3)30N at 50CM 4)60N at 70 CM. |

P.Velmurugan said: (Sep 30, 2011) | |

Resolve a force of 200N into two components making angles of 60deg and 45deg with it on opposite sides. |

Prince Tetteh said: (Mar 13, 2015) | |

The weight of the object is experienced throughout the string in the pulley. W = mg = 10*9.81 = 98.1 N. Summation of forces along x-axis = 0. F(AB) cos$-98.1 cos45-98.1 cos75 = 0. F(AB) cos$ = 94.757 N ------- Equation 1. Summation of forces along y-axis = 0. F(AB) sin$-98.1sin75+98.1sin45 = 0. F(AB) sin$ = 25.39 N -------- Equation 2. Equation 2/Equation 1. tan$ = 0.2679 $ = 15 deg. From Equation 1. F(AB) = 94.757/cos15 = 98.09 N. Therefore D. |

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