Electronics - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 4)
4.
Increasing the number of turns of wire on the secondary of a transformer will
Discussion:
13 comments Page 1 of 2.
Jeet said:
1 decade ago
Because I is inversely proportional to no. of turns.
Velan said:
1 decade ago
Es/Ep = Ns/Np = Ip/Is
V increase I decrease
N(no of turns) increase V increase
V increase I decrease
N(no of turns) increase V increase
Sukumar said:
1 decade ago
I think this effect the primary current in the form of increasing.
Am I right?
Am I right?
Avinash said:
1 decade ago
In this case the ratio Ip/Is will increase but it will not affect the primary current as no.of turns in the primary is same.
Ramya Wijesundera said:
1 decade ago
The number of turns are more resistance is more so the current is less. Further, when number of turns are more generated e.m.f. is more.
Therefore, according to the equation P=VI, secondary I (current) should be less than primary current because power is not increasing.
Therefore, according to the equation P=VI, secondary I (current) should be less than primary current because power is not increasing.
Vijay kumar said:
1 decade ago
We know that in a transformer,
Ns/Np = Ip/Is.
From the above relation, The relation btwn no.of turns and current is inversely propotional to each other.
Ns/Np = Ip/Is.
From the above relation, The relation btwn no.of turns and current is inversely propotional to each other.
Purnima said:
1 decade ago
If no of turn is increase then the resistance is also increases thats why the current is decreases.
Ravi kumar said:
1 decade ago
Because I is inversely proportional to no.of turns.
(1)
Veera said:
1 decade ago
The work of resistance is its oppose the current. So only resistance is increasing means current is decreasing.
Rudresh.R said:
1 decade ago
How Np/Ns=vp/vs?
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