Because I is inversely proportional to no. of turns.

Velan said:
(Aug 21, 2011)

Es/Ep = Ns/Np = Ip/Is

V increase I decrease
N(no of turns) increase V increase

Sukumar said:
(Feb 24, 2012)

I think this effect the primary current in the form of increasing.

Am I right?

Avinash said:
(Apr 8, 2012)

In this case the ratio Ip/Is will increase but it will not affect the primary current as no.of turns in the primary is same.

Ramya Wijesundera said:
(Apr 26, 2012)

The number of turns are more resistance is more so the current is less. Further, when number of turns are more generated e.m.f. is more.

Therefore, according to the equation P=VI, secondary I (current) should be less than primary current because power is not increasing.

Vijay Kumar said:
(May 25, 2012)

We know that in a transformer,
Ns/Np = Ip/Is.
From the above relation, The relation btwn no.of turns and current is inversely propotional to each other.

Purnima said:
(Aug 17, 2012)

If no of turn is increase then the resistance is also increases thats why the current is decreases.

Ravi Kumar said:
(Feb 28, 2013)

Because I is inversely proportional to no.of turns.

Veera said:
(Mar 8, 2014)

The work of resistance is its oppose the current. So only resistance is increasing means current is decreasing.

Rudresh.R said:
(Jan 23, 2015)

How Np/Ns=vp/vs?

Krishna Chilakabattini said:
(Mar 30, 2015)

V1/V2 = I2/I1 = N1/N2.

Malik said:
(Sep 18, 2015)

If we give 220 on primary 100 turns and we take from secondary 110 and what should be no of turns of secondary winding.

Buba said:
(Mar 4, 2017)

Answer incorrect, without load increasing turns of secondary doesn't change any current.

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