Electronics - Transformers - Discussion

Discussion Forum : Transformers - General Questions (Q.No. 5)
5.
What is the turns ratio of the transformer needed to match a 1 komega.gif source resistance to a 160 omega.gif load?
2.5:1
0.4:1
6.25:1
16:1
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
30 comments Page 1 of 3.

Historia said:   3 years ago
0.4:1 is for (Ns/Np)^2 = Zs/Zp.
2.5:1 is for (Np/Ns)^2 = Zp/Zs.

I think that both of them are correct, the only mistake is putting both of them in the choices that is why it got a little confusing.

Stahka said:   4 years ago
The followed formula is Ns/Np = underroot of Zs/Zp;

Thus Zs si Zload which is 160 ohms and Zp is 1kohms.

Answer is 0.4:1.
(1)

Poonam said:   6 years ago
(N1/N2)^2 = R2/R1.

So the answer is option B.

Shadan said:   6 years ago
Answer should be a Turn and transform ratio is same N1/N2.

So answer A.

Shadan said:   6 years ago
N2/N1 = turn ratio.
N1/N2 = Transformation ratio.
N2/N1=under root R2/R1.
SO 0.4:1.

Shadan said:   6 years ago
According to me, the answer should be A.

Satya said:   7 years ago
N2/N1= √(r2/r1) = k.

Dinesh Rai said:   7 years ago
Is * 1000 = Ip * 160 and Ip/Is = k = N1/N2.
k = 1000/160 = 6.25:1.

Shreyas said:   8 years ago
k = sqrt(r2/r1).
k = sqrt(160/1000),
k = 0.4.

Therefore ratio will be 0.4:1.

Xyz said:   8 years ago
N2/N1 = V2/V1 = I1/I2 = K = SQR OF Rload/Rsource.


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