Electronics - Transformers - Discussion

Discussion Forum : Transformers - General Questions (Q.No. 5)
5.
What is the turns ratio of the transformer needed to match a 1 komega.gif source resistance to a 160 omega.gif load?
2.5:1
0.4:1
6.25:1
16:1
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
30 comments Page 3 of 3.

Naga Jyothi said:   1 decade ago
sir..........
(N1/N2)^2=R1/R2
ABOVE ANSWER IS CORRECT SIR....
N1/N2=2.5:1

Jagadeesh said:   1 decade ago
Z1/Z2=(N1/N2)^2
(1000/160)=(N1/N2)
^2
N1/N2=2.5:1
is the correct answer

Sukumar said:   1 decade ago
I think right option is A because we know that direct formulae rp/rs=(Np/Ns)^2
rp=1000;
rs=160;
(Np/Ns)^2=(1000/160)--->6.25/1;
then Np/Ns=2.5:1

Guest said:   1 decade ago
Therefore Is*1000=Ip*160 and Ip/Is=k=N1/N2
k=1000/160=6.25:1

R&J said:   1 decade ago
Answer is c because IpRp=IsRs

therefore Is*1000=Ip*160 and Ip/Is=k=N1/N2
k=1000/160=6.25:1

Arudra laxmi said:   1 decade ago
Saritha I think your answer is wrong once you calculate again.

Saritha said:   1 decade ago
r2=160,r1=1000

k=(160/1000)^0.5

k=0.4

Sachi said:   1 decade ago
Elaborate the theory in it please.

LAVISHA said:   1 decade ago
Option c because N IS INVERSELY PROPOTIONAL TO THE RESISTSNCE.

Billa said:   1 decade ago
Please explain.


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