Electronics - Time Response of Reactive Circuits - Discussion
Discussion Forum : Time Response of Reactive Circuits - General Questions (Q.No. 4)
4.
In a repetitive-pulse RC integrator circuit, what would the steady-state voltage equal at the end of the fifth pulse? Assume a Vin of 20 V.
Discussion:
7 comments Page 1 of 1.
Vasu said:
1 decade ago
Can anyone explain this ?
Sneha said:
1 decade ago
Please help me with the solution.
Promod said:
10 years ago
Please help me to solve this question.
Girish G said:
9 years ago
Anyone explain the answer.
Sandhyarani nayak said:
9 years ago
Please solve this problem with the explanation.
Divyanshu Shekhar said:
9 years ago
First pulse => During the first pulse, the capacitor charges. The output voltage reaches,
12.64 V (63.2% of 20 V).
Between first and second pulses => The capacitor discharges and the voltage decreases to 36.8% of the voltage at the beginning of this interval: 0.368 (12. 64 V) = 4.65 V.
Second pulse => (20 - 4.65) V = 15.35 V.
Between second and third pulse = > 0.368 (15.35) = 5.64 V.
Third pulse => (20 - 5.64) v = 14.36 V.
Between third and fourth pulse => 0.368 * (14.36) = 5.28 V.
Fourth pulse => (20 - 5.28) V = 14.72 V.
Between fourth and fifth pulse => 0.368 (14.72) = 5.41 V.
Fifth pulse => (20 - 5.41) V = 14.59 V.
=> 14.6 V approx.
12.64 V (63.2% of 20 V).
Between first and second pulses => The capacitor discharges and the voltage decreases to 36.8% of the voltage at the beginning of this interval: 0.368 (12. 64 V) = 4.65 V.
Second pulse => (20 - 4.65) V = 15.35 V.
Between second and third pulse = > 0.368 (15.35) = 5.64 V.
Third pulse => (20 - 5.64) v = 14.36 V.
Between third and fourth pulse => 0.368 * (14.36) = 5.28 V.
Fourth pulse => (20 - 5.28) V = 14.72 V.
Between fourth and fifth pulse => 0.368 (14.72) = 5.41 V.
Fifth pulse => (20 - 5.41) V = 14.59 V.
=> 14.6 V approx.
(1)
Bucketzz said:
6 years ago
Thank you @Divyanshu Shekhar.
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