Electronics - Time Response of Reactive Circuits - Discussion

4. 

In a repetitive-pulse RC integrator circuit, what would the steady-state voltage equal at the end of the fifth pulse? Assume a Vin of 20 V.

[A]. 1.46 V
[B]. 14.62 V
[C]. 20 V
[D]. 0 V

Answer: Option B

Explanation:

No answer description available for this question.

Vasu said: (Oct 13, 2011)  
Can anyone explain this ?

Sneha said: (Jul 27, 2015)  
Please help me with the solution.

Promod said: (Apr 9, 2016)  
Please help me to solve this question.

Girish G said: (Aug 11, 2016)  
Anyone explain the answer.

Sandhyarani Nayak said: (Nov 10, 2016)  
Please solve this problem with the explanation.

Divyanshu Shekhar said: (Nov 23, 2016)  
First pulse => During the first pulse, the capacitor charges. The output voltage reaches,
12.64 V (63.2% of 20 V).

Between first and second pulses => The capacitor discharges and the voltage decreases to 36.8% of the voltage at the beginning of this interval: 0.368 (12. 64 V) = 4.65 V.
Second pulse => (20 - 4.65) V = 15.35 V.

Between second and third pulse = > 0.368 (15.35) = 5.64 V.
Third pulse => (20 - 5.64) v = 14.36 V.

Between third and fourth pulse => 0.368 * (14.36) = 5.28 V.
Fourth pulse => (20 - 5.28) V = 14.72 V.

Between fourth and fifth pulse => 0.368 (14.72) = 5.41 V.
Fifth pulse => (20 - 5.41) V = 14.59 V.

=> 14.6 V approx.

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