Electronics - Time Response of Reactive Circuits - Discussion
Discussion Forum : Time Response of Reactive Circuits - General Questions (Q.No. 1)
1.
What voltage will the capacitor charge up to in the given circuit for the single input pulse shown?
Discussion:
17 comments Page 1 of 2.
Phaneendra said:
1 decade ago
f=1/RC
Toff=1/f
Ton+Toff=T;32.4+16.2=48.6
Ton/T=Von(drop)
beacause we hav calucalate voltge during on state .
V-Von=4.3v
5-0.66=4.3v
Toff=1/f
Ton+Toff=T;32.4+16.2=48.6
Ton/T=Von(drop)
beacause we hav calucalate voltge during on state .
V-Von=4.3v
5-0.66=4.3v
Elkaa said:
1 decade ago
Dear,
If the timeconstant = RC is 16.4 usec, and the pulse is 32.4 usec, then I would expect that the capacitor charges up to Vin, as it has a lot more time then RC.
Please confirm.
If the timeconstant = RC is 16.4 usec, and the pulse is 32.4 usec, then I would expect that the capacitor charges up to Vin, as it has a lot more time then RC.
Please confirm.
Sreekumar said:
1 decade ago
I agree with Elkaa, it will charge upto Vin.
Nitesh said:
1 decade ago
Vc(voltage across capacitor) = V0(1-e-t/to)
Vasu said:
1 decade ago
Can anyone explain this in brief please.
Ganesh said:
1 decade ago
I agree with elka.
Mehta said:
1 decade ago
Elkaa is totally wrong. It takes 5 timeconstant to charge upto Vin.
So it won't charge upto Vin.
Nitesh is right. In that equation substitute t = 32.8us and to = RC = 16.4us.
So it won't charge upto Vin.
Nitesh is right. In that equation substitute t = 32.8us and to = RC = 16.4us.
Leena said:
1 decade ago
Writing the kirchoff's current law you get Vin-iR-(1/C) inetgral (idt).
On applying the laplace transform we get the equation,
Vo(1-e-t/to).
On substituting we get 4.3.
Where to = 1/RC.
Vo = 5.
On applying the laplace transform we get the equation,
Vo(1-e-t/to).
On substituting we get 4.3.
Where to = 1/RC.
Vo = 5.
Arun said:
1 decade ago
@Mehta is right. Given circuit is a low pass filter circuit.
So output voltage is:
Vo = Vin (1-e^(-t/RC)).
T = 32.8 us.
R = 82 k.
C = 200 PF.
So output voltage is:
Vo = Vin (1-e^(-t/RC)).
T = 32.8 us.
R = 82 k.
C = 200 PF.
Gaurav said:
10 years ago
T constant = rc = 82 k x 200 pf = 16.4 micro sec.
Plus time = 32.8 micro sec.
Trc = 32.8/16.4 = 2.
1 Trc = 63.3%.
2 Trc = 86%.
So, output voltage = 5x(86/100) = 4.3 v.
Plus time = 32.8 micro sec.
Trc = 32.8/16.4 = 2.
1 Trc = 63.3%.
2 Trc = 86%.
So, output voltage = 5x(86/100) = 4.3 v.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers