Electronics - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - Filling the Blanks (Q.No. 11)
11.
The bandwidth is ______ in the given circuit.
Discussion:
3 comments Page 1 of 1.
Vishal said:
7 years ago
BW = R/2πL.
BW = (33 + 7) / (2π * 1.8 * 10^-3),
BW = 3.536KHz.
BW = (33 + 7) / (2π * 1.8 * 10^-3),
BW = 3.536KHz.
KIRAN V said:
9 years ago
Q = Fr/B.W.
Fr = 1/2 * pi * Sq.(LC).
Q = 1/R * Sq.(L/C).
Rt = R1 + Rw = 33 + 7 = 40 Ohm.
Finally, B.W = R/2 * pi * L.
B.W = 40/(6.28 * 1.8 * 10^-3),
B.W = 3.5385 KHz.
Fr = 1/2 * pi * Sq.(LC).
Q = 1/R * Sq.(L/C).
Rt = R1 + Rw = 33 + 7 = 40 Ohm.
Finally, B.W = R/2 * pi * L.
B.W = 40/(6.28 * 1.8 * 10^-3),
B.W = 3.5385 KHz.
Krishna kumar said:
1 decade ago
This question can be solved by these formula,
Q= Fr/B.W
Where Fr = Resonant frequency.
B.W = Bandwidth.
Q= Fr/B.W
Where Fr = Resonant frequency.
B.W = Bandwidth.
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