Electronics - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 2)
2.
What is the bandwidth of the circuit?
Discussion:
34 comments Page 3 of 4.
Abdullah said:
4 years ago
The bandwidth formula can be rearranged to R/(2*π*L).
Maddy said:
1 decade ago
@Lalit from ur formulas I got 142Hz ans.
Is that ri8?
Is that ri8?
Sachin said:
3 years ago
W2-W1 = R/L.
BandWidth = F2 - F1 = R/(2 * π * L).
BandWidth = F2 - F1 = R/(2 * π * L).
(1)
Manjunath said:
1 decade ago
Bandwidth = R/2*pi*L . BW= 1/2*3.14*5 = 31.8 Hz.
Dhana said:
1 decade ago
XL=wL.
XL=(2*pi*f)(5H).
XL=2*22/7*5.
XL=31.42 app.
XL=(2*pi*f)(5H).
XL=2*22/7*5.
XL=31.42 app.
Krupal gowda jedrali said:
1 decade ago
= r/2.pai.L formula.
= 1000/2*pai*5 = 31.8105 hz.
= 1000/2*pai*5 = 31.8105 hz.
Alka said:
1 decade ago
BW=fr/Q
Q=(2*pi*fr*L)/R
Bw=R/(2*pi*L)
=31.83
Q=(2*pi*fr*L)/R
Bw=R/(2*pi*L)
=31.83
Ashish said:
8 years ago
Here, r/2 * π * L = 31.8.
(1)
SUMA said:
7 years ago
Here, R/(2*π*L) = 31.8.
Sap said:
1 decade ago
Hussain you are right.
(1)
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