Electronics - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 2)
2.
What is the bandwidth of the circuit?
Discussion:
34 comments Page 1 of 4.
Govind Singh Chouhan said:
1 decade ago
Data Given:
R = 1k.
C = 1uF.
L = 5H.
So, resonance freq. is = 1/2*pi*sqrt(LC).
(fo is a resonance freq.)
fo = 1/2*3.14*sqrt(5*1*10^-6)).
fo = 1/2*3.14*sqrt(0.000005).
fo = 71.42Hz.
we know about the Quality factor "Q",
Q = WoL/R.
Q = 2*pi*fo*5/1k.
Q = 2.24.
The relationship between Q,fo and BW is:
Q = fo/BW.
So BW = fo/Q.
BW = 71.42/2.24.
BW = 31.88Hz.
R = 1k.
C = 1uF.
L = 5H.
So, resonance freq. is = 1/2*pi*sqrt(LC).
(fo is a resonance freq.)
fo = 1/2*3.14*sqrt(5*1*10^-6)).
fo = 1/2*3.14*sqrt(0.000005).
fo = 71.42Hz.
we know about the Quality factor "Q",
Q = WoL/R.
Q = 2*pi*fo*5/1k.
Q = 2.24.
The relationship between Q,fo and BW is:
Q = fo/BW.
So BW = fo/Q.
BW = 71.42/2.24.
BW = 31.88Hz.
Laurent p .Eranga said:
10 years ago
First find fr = 1/6.28 times square root of LC.
You will got 71.2 hz.
Then find xl = 6.28 times fl you will got 2.23 k if xl = xc.
Then q = xl/r you will got 2.23 k/1 k = 2.235.
If the formula for bw = fr/q.
fr = 71.2 and q = 2.235 so bw = fr/q will be equals to 31.8 hz.
You will got 71.2 hz.
Then find xl = 6.28 times fl you will got 2.23 k if xl = xc.
Then q = xl/r you will got 2.23 k/1 k = 2.235.
If the formula for bw = fr/q.
fr = 71.2 and q = 2.235 so bw = fr/q will be equals to 31.8 hz.
Hussain said:
1 decade ago
BW = fr/Q; ---- @Aysha: i agree with u
Q ---- quality factor, higher the quality factor lower the Bandwidth.
Q = (1/R)*(sqrt(L/c));
fr = 1/(2*pi*sqrt(LC)); ---- resonant frequency.
so BW = R/(2*pi*L);
so on substituting the values BW = 31.8 Hz
Q ---- quality factor, higher the quality factor lower the Bandwidth.
Q = (1/R)*(sqrt(L/c));
fr = 1/(2*pi*sqrt(LC)); ---- resonant frequency.
so BW = R/(2*pi*L);
so on substituting the values BW = 31.8 Hz
Gaurav Kumar Yadav said:
1 decade ago
As Bandwidth = Resonant frequency/Quality Factor.
And Resonant Frequency = 1/(2*pi*Sqareroot LC).
And Quality factor = 1/R*squareroot(L/C).
Now BW = 1/ (2*pi*Suareroot LC)/1/R*squareroot (L/C) = R/(2*pi*L).
BW = 1000/(2*3.14*5) = 31.8 Hz.
And Resonant Frequency = 1/(2*pi*Sqareroot LC).
And Quality factor = 1/R*squareroot(L/C).
Now BW = 1/ (2*pi*Suareroot LC)/1/R*squareroot (L/C) = R/(2*pi*L).
BW = 1000/(2*3.14*5) = 31.8 Hz.
Ruben said:
1 decade ago
So, when you decrease the resistance in the circuit Q will increase and bandwidth and will decrease, but phase angle theta will increase. The circuit efficiency will decrease number.
Amrita said:
1 decade ago
BANDWIDTH= Resonant freq/ Quality Factor
Resonant Frequency= 1/(2*pi*sqrt of(L*C))
Quality Factor= 1/R*(sqrt(L/C))
Using above fomula we can determine, Bandwidth=31.83 .
Resonant Frequency= 1/(2*pi*sqrt of(L*C))
Quality Factor= 1/R*(sqrt(L/C))
Using above fomula we can determine, Bandwidth=31.83 .
Oneidensis said:
1 decade ago
My answer is 200... iIve been solving this so many times.. here's the formulas I used,
f=1/(square roof of (LC))
then,
Q= (1/fRC) ; Q= (fL/R)
then,
B=f/Q... B=200
f=1/(square roof of (LC))
then,
Q= (1/fRC) ; Q= (fL/R)
then,
B=f/Q... B=200
Seenivasagan said:
1 decade ago
Bandwidth(BW)=fr/Q
Q=(2*pi*fr*L)/R
fr=1/(2*pi*root LC)
by applying this ,
we can get fr=71.21
Q=2.236
BW=fr/Q
=71.21/2.236
=31.84
approximately 31.8
Q=(2*pi*fr*L)/R
fr=1/(2*pi*root LC)
by applying this ,
we can get fr=71.21
Q=2.236
BW=fr/Q
=71.21/2.236
=31.84
approximately 31.8
FADI said:
1 decade ago
B.W=FR/Q
Q=(1/R)SQRT(L/C)
FR=1/2*PI*SQRT(LC)
B.W=[1/2*PI*SQRT(LC)]/(1/R)SQRT(L/C)
B.W=R*SQRT C / 2*PI*L*SQRT C
B.W=R/2*PI*L
Q=(1/R)SQRT(L/C)
FR=1/2*PI*SQRT(LC)
B.W=[1/2*PI*SQRT(LC)]/(1/R)SQRT(L/C)
B.W=R*SQRT C / 2*PI*L*SQRT C
B.W=R/2*PI*L
M.V.KRISHNA said:
1 decade ago
BW=fr/Q;
fr=1/(2*pi*underroot(L*C));
Q=(1/R)*underroot(L/C);
BW=R/(2*pi*L);
=>1Kohm/(2*pi*5H);
=32.3Hz
fr=1/(2*pi*underroot(L*C));
Q=(1/R)*underroot(L/C);
BW=R/(2*pi*L);
=>1Kohm/(2*pi*5H);
=32.3Hz
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers