Electronics - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 2)
2.
What is the bandwidth of the circuit?
Discussion:
34 comments Page 1 of 4.
Bogart said:
6 months ago
fr = QBW.
BW = fr/Q.
fr = 1/2π √LC..
Q=(1/R)(√ of L/C).
BW = fr/Q.
fr = 1/2π √LC..
Q=(1/R)(√ of L/C).
Sachin said:
3 years ago
W2-W1 = R/L.
BandWidth = F2 - F1 = R/(2 * π * L).
BandWidth = F2 - F1 = R/(2 * π * L).
(1)
Abdullah said:
4 years ago
The bandwidth formula can be rearranged to R/(2*π*L).
Jyothi said:
5 years ago
BW = R/(2*π*L),
BW = (1*10^3)/(2*π*5),
=31.83Hz.
BW = (1*10^3)/(2*π*5),
=31.83Hz.
(1)
PRITAM said:
5 years ago
Q=XL/R.
BW=fr/Q.
fr=1/2*pi*√LC=71.17.
XL=WL=2235.87,
Q=XL/R=2.23.
B=71.17/2.23=31.83.
BW=fr/Q.
fr=1/2*pi*√LC=71.17.
XL=WL=2235.87,
Q=XL/R=2.23.
B=71.17/2.23=31.83.
SUMA said:
7 years ago
Here, R/(2*π*L) = 31.8.
Ayush Purwar said:
8 years ago
Bandwidth= R/(2*L)...Hz.
= 1000/(2*3.14*5).
= 31.84 Hz.
= 1000/(2*3.14*5).
= 31.84 Hz.
Mody shaban said:
8 years ago
HOW?
Vijay said:
8 years ago
Q=(omega*L)/R.
BW=f/Q,
=> BW=(f*R)/(w*L)
=> BW=R/(2*pi*L)
=> Bw=31.8.
BW=f/Q,
=> BW=(f*R)/(w*L)
=> BW=R/(2*pi*L)
=> Bw=31.8.
Ashish said:
8 years ago
Here, r/2 * π * L = 31.8.
(1)
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