Electronics - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 2)
2.
What is the bandwidth of the circuit?
Discussion:
34 comments Page 2 of 4.
Ayush Purwar said:
8 years ago
Bandwidth= R/(2*L)...Hz.
= 1000/(2*3.14*5).
= 31.84 Hz.
= 1000/(2*3.14*5).
= 31.84 Hz.
PRITAM said:
5 years ago
Q=XL/R.
BW=fr/Q.
fr=1/2*pi*√LC=71.17.
XL=WL=2235.87,
Q=XL/R=2.23.
B=71.17/2.23=31.83.
BW=fr/Q.
fr=1/2*pi*√LC=71.17.
XL=WL=2235.87,
Q=XL/R=2.23.
B=71.17/2.23=31.83.
LALIT GARG said:
1 decade ago
As Q=B.W/fr
so fr=1/(2pie*underroot of LC)
And Q=UNDERROOT OF L/(R*UNDERROOT OF C)
B.W=?
so fr=1/(2pie*underroot of LC)
And Q=UNDERROOT OF L/(R*UNDERROOT OF C)
B.W=?
Sreeyush Sudhakaran said:
1 decade ago
B.W=fr/Q
Q=(2*Pi*fr*L)/R
B.W = fr/((2*Pi*fr*L)/R) = R/2*Pi*L = 1000/2*3.14*5 = 31.8Hz
Q=(2*Pi*fr*L)/R
B.W = fr/((2*Pi*fr*L)/R) = R/2*Pi*L = 1000/2*3.14*5 = 31.8Hz
Vijay said:
8 years ago
Q=(omega*L)/R.
BW=f/Q,
=> BW=(f*R)/(w*L)
=> BW=R/(2*pi*L)
=> Bw=31.8.
BW=f/Q,
=> BW=(f*R)/(w*L)
=> BW=R/(2*pi*L)
=> Bw=31.8.
Shah said:
1 decade ago
B' = R/L in radians.
B' = 1000/5.
B' = 200.
B = B'/2*pi.
B = 200/2*pi.
B = 31.83.
B' = 1000/5.
B' = 200.
B = B'/2*pi.
B = 200/2*pi.
B = 31.83.
Bogart said:
6 months ago
fr = QBW.
BW = fr/Q.
fr = 1/2π √LC..
Q=(1/R)(√ of L/C).
BW = fr/Q.
fr = 1/2π √LC..
Q=(1/R)(√ of L/C).
Daks said:
1 decade ago
Easy way.
BW = Fr/Q
BW = 1/2*pi*L/R
BW = R/2*pi*L
BW = 31.83
BW = Fr/Q
BW = 1/2*pi*L/R
BW = R/2*pi*L
BW = 31.83
Jyothi said:
5 years ago
BW = R/(2*π*L),
BW = (1*10^3)/(2*π*5),
=31.83Hz.
BW = (1*10^3)/(2*π*5),
=31.83Hz.
(1)
Sandeep said:
1 decade ago
Q=Fr/BW;
BW=Fr/Q;
Fr=1/2*PI*ROOT(L*C);
Q=(1/R)(ROOT(L/C));
BW=Fr/Q;
Fr=1/2*PI*ROOT(L*C);
Q=(1/R)(ROOT(L/C));
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