Electronics - RL Circuits - Discussion
Discussion Forum : RL Circuits - General Questions (Q.No. 4)
4.
If XL= 100 
and R = 100 , then impedance will be
and R = 100 , then impedance will be141.4
14.14
100
200
Discussion:
9 comments Page 1 of 1.
Rajan said:
9 years ago
Another way to express this is due to Resistor and Inductance current flow are not in the same phase they can be shown as below. Total impedance cannot be plus but use trigonometric equation,
Z^2 = Xl^2 R^2.
Z = sqr(Xl^2 R^2).
Z = sqr(100 * 100 + 100 * 100) = sqr(20000) = 141.4 ohms.
Z^2 = Xl^2 R^2.
Z = sqr(Xl^2 R^2).
Z = sqr(100 * 100 + 100 * 100) = sqr(20000) = 141.4 ohms.
Chandan said:
1 decade ago
z=sqrt(R^2+X^2),then z=sqrt(100^2+100^2)
therefore z=sqrt(20000) so implies sqrt(10000*2)
100sqrt(2) i.e100*1.414=141.4
therefore z=sqrt(20000) so implies sqrt(10000*2)
100sqrt(2) i.e100*1.414=141.4
Damilare said:
8 years ago
z = sqrt(r squared +XL squared),
Substituting values,we have;
z = sqrt(20000),
z = 141.4ohms.
Substituting values,we have;
z = sqrt(20000),
z = 141.4ohms.
Swat said:
7 years ago
z= √(r^2+Xl^2).
=√(100^2+100^2).
=√20000).
= 141.4.
=√(100^2+100^2).
=√20000).
= 141.4.
Gangadharmanu said:
8 years ago
Z =√(r^2*+l^2).
=√(100*100+100*100).
=√(20000).
=141.4.
=√(100*100+100*100).
=√(20000).
=141.4.
Jyothi said:
10 years ago
R = 100 XL = 100.
Z = sqr(100*100+100*100) = sqr(20000) = 141.4 ohms.
Z = sqr(100*100+100*100) = sqr(20000) = 141.4 ohms.
Gautham said:
1 decade ago
If Z=sqrt(R^2+X^2), then Z=sqrt(100^2+100^2)
Therefore, Z=200. Right?
Therefore, Z=200. Right?
M.Rizwan Mukati said:
1 decade ago
Z = R+jXL.
Then convert it into polar form.
Then convert it into polar form.
Ranjit said:
1 decade ago
Z=sqrt(R2 + X2)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers